OCR MEI D2 2009 June — Question 1 16 marks

Exam BoardOCR MEI
ModuleD2 (Decision Mathematics 2)
Year2009
SessionJune
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
DifficultyEasy -2.5 This question is from Decision Mathematics 2, not Groups/Further Pure, and contains basic logic/Boolean algebra exercises. Parts (a) and (b) are trivial comprehension and circuit drawing tasks, while part (c) is a mechanical truth table construction requiring no problem-solving insight—well below typical A-level maths difficulty.
Spec1.01b Logical connectives: congruence, if-then, if and only if

1
  1. The following was said in a charity appeal on Radio 4 in October 2006.
    "It is hard to underestimate the effect that your contribution will make."
    Rewrite the comment more simply in your own words without changing its meaning.
  2. A machine has three components, A, B and C, each of which is either active or inactive.
    The states (active or inactive) of the components and the machine are to be modelled by a combinatorial circuit in which "active" is represented by "true" and "inactive" is represented by "false". Draw such a circuit.
  3. Construct a truth table to show the following. $$[ ( ( \mathrm { a } \wedge \mathrm {~b} ) \vee ( ( \sim \mathrm { a } ) \wedge \mathrm { c } ) ) \vee ( ( \sim \mathrm { b } ) \wedge \mathrm { c } ) ] \Leftrightarrow \sim [ ( ( \sim \mathrm { a } ) \wedge ( \sim \mathrm { c } ) ) \vee ( ( \sim \mathrm { b } ) \wedge ( \sim \mathrm { c } ) ) ]$$

Question 1:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
"It is hard to overestimate the effect..." or equivalent e.g. "Your contribution will make a significant effect"B2 B1 for recognising the double negative; B2 for a clear correct statement
Part (b)
AnswerMarks Guidance
AnswerMarks Guidance
Expression: \((a \wedge b) \vee ((\sim a) \wedge c) \vee ((\sim b) \wedge c)\) identifiedB1 For correct logical expression
Correct circuit drawn with AND gates for \(a \wedge b\), \((\sim a) \wedge c\), \((\sim b) \wedge c\)M1 For attempting three AND combinations
NOT gates on \(a\) and \(b\)B1
Three AND gates correctly connectedB1
Three OR gates combining outputsB1
Fully correct circuitA2
Part (c)
AnswerMarks Guidance
AnswerMarks Guidance
Columns for \(a\), \(b\), \(c\), \(a \wedge b\), \(\sim a\), \(\sim b\), \(\sim c\)B1 For correct intermediate columns
Column for \((\sim a) \wedge c\) correctB1
Column for \((\sim b) \wedge c\) correctB1
LHS column correctB1
Column for \((\sim a) \wedge (\sim c)\) correctB1
Column for \((\sim b) \wedge (\sim c)\) correctB1
RHS column correct and matches LHSB1 Full verification
# Question 1:

## Part (a)
| Answer | Marks | Guidance |
|--------|-------|----------|
| "It is hard to **over**estimate the effect..." or equivalent e.g. "Your contribution will make a significant effect" | B2 | B1 for recognising the double negative; B2 for a clear correct statement |

## Part (b)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Expression: $(a \wedge b) \vee ((\sim a) \wedge c) \vee ((\sim b) \wedge c)$ identified | B1 | For correct logical expression |
| Correct circuit drawn with AND gates for $a \wedge b$, $(\sim a) \wedge c$, $(\sim b) \wedge c$ | M1 | For attempting three AND combinations |
| NOT gates on $a$ and $b$ | B1 | |
| Three AND gates correctly connected | B1 | |
| Three OR gates combining outputs | B1 | |
| Fully correct circuit | A2 | |

## Part (c)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Columns for $a$, $b$, $c$, $a \wedge b$, $\sim a$, $\sim b$, $\sim c$ | B1 | For correct intermediate columns |
| Column for $(\sim a) \wedge c$ correct | B1 | |
| Column for $(\sim b) \wedge c$ correct | B1 | |
| LHS column correct | B1 | |
| Column for $(\sim a) \wedge (\sim c)$ correct | B1 | |
| Column for $(\sim b) \wedge (\sim c)$ correct | B1 | |
| RHS column correct and matches LHS | B1 | Full verification |

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1
\begin{enumerate}[label=(\alph*)]
\item The following was said in a charity appeal on Radio 4 in October 2006.\\
"It is hard to underestimate the effect that your contribution will make."\\
Rewrite the comment more simply in your own words without changing its meaning.
\item A machine has three components, A, B and C, each of which is either active or inactive.

\begin{itemize}
  \item The machine is active if A and B are both active.
  \item The machine is active if A is inactive and C is active.
  \item The machine is active if B is inactive and C is active.
  \item Otherwise the machine is inactive.
\end{itemize}

The states (active or inactive) of the components and the machine are to be modelled by a combinatorial circuit in which "active" is represented by "true" and "inactive" is represented by "false".

Draw such a circuit.
\item Construct a truth table to show the following.

$$[ ( ( \mathrm { a } \wedge \mathrm {~b} ) \vee ( ( \sim \mathrm { a } ) \wedge \mathrm { c } ) ) \vee ( ( \sim \mathrm { b } ) \wedge \mathrm { c } ) ] \Leftrightarrow \sim [ ( ( \sim \mathrm { a } ) \wedge ( \sim \mathrm { c } ) ) \vee ( ( \sim \mathrm { b } ) \wedge ( \sim \mathrm { c } ) ) ]$$
\end{enumerate}

\hfill \mbox{\textit{OCR MEI D2 2009 Q1 [16]}}