OCR D2 2010 January — Question 5 16 marks

Exam BoardOCR
ModuleD2 (Decision Mathematics 2)
Year2010
SessionJanuary
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
DifficultyEasy -1.8 This is a straightforward game theory question requiring only basic calculations: finding row/column minima and maxima for play-safe strategies, computing expected values with given probabilities, and solving a simple linear equation for optimal mixed strategy. All techniques are routine applications of standard algorithms with no conceptual difficulty or novel insight required.
Spec7.08a Pay-off matrix: zero-sum games7.08b Dominance: reduce pay-off matrix7.08c Pure strategies: play-safe strategies and stable solutions7.08d Nash equilibrium: identification and interpretation7.08e Mixed strategies: optimal strategy using equations or graphical method

5 Robbie received a new computer game for Christmas. He has already worked through several levels of the game but is now stuck at one of the levels in which he is playing against a character called Conan. Robbie has played this particular level several times. Each time Robbie encounters Conan he can choose to be helped by a dwarf, an elf or a fairy. Conan chooses between being helped by a goblin, a hag or an imp. The players make their choices simultaneously, without knowing what the other has chosen. Robbie starts the level with ten gold coins. The table shows the number of gold coins that Conan must give Robbie in each encounter for each combination of helpers (a negative entry means that Robbie gives gold coins to Conan). If Robbie's total reaches twenty gold coins then he completes the level, but if it reaches zero the game ends. This means that each attempt can be regarded as a zero-sum game.
Conan
\cline { 2 - 5 }GoblinHagImp
\cline { 2 - 5 }Dwarf- 1- 42
\cline { 2 - 5 } RobbieElf31- 4
\cline { 2 - 5 }Fairy1- 11
\cline { 2 - 5 }
\cline { 2 - 5 }
  1. Find the play-safe choice for each player, showing your working. Which helper should Robbie choose if he thinks that Conan will play-safe?
  2. How many gold coins can Robbie expect to win, with each choice of helper, if he thinks that Conan will choose randomly between his three choices (so that each has probability \(\frac { 1 } { 3 }\) )? Robbie decides to choose his helper by using random numbers to choose between the elf and the fairy, where the probability of choosing the elf is \(p\) and the probability of choosing the fairy is \(1 - p\).
  3. Write down an expression for the expected number of gold coins won at each encounter by Robbie for each of Conan's choices. Calculate the optimal value of \(p\). Robbie's girlfriend thinks that he should have included the possibility of choosing the dwarf. She denotes the probability with which Robbie should choose the dwarf, the elf and the fairy as \(x , y\) and \(z\) respectively. She then models the problem of choosing between the three helpers as the following LP. $$\begin{aligned} \text { Maximise } & M = m - 4 , \\ \text { subject to } & m \leqslant 3 x + 7 y + 5 z \\ & m \leqslant 5 y + 3 z \\ & m \leqslant 6 x + 5 z \\ & x + y + z \leqslant 1 , \\ \text { and } & m \geqslant 0 , x \geqslant 0 , y \geqslant 0 , z \geqslant 0 . \end{aligned}$$
  4. Explain how the expression \(3 x + 7 y + 5 z\) was formed. Robbie's girlfriend uses the Simplex algorithm to solve the LP problem. Her solution has \(x = 0\) and \(y = \frac { 2 } { 7 }\).
  5. Calculate the optimal value of \(M\).

Question 5:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
Calculating row minimaM1 cao
Calculating column maxima (or their negatives)M1 cao
Play-safe for Robbie is fairy; Play-safe for Conan is hagA1, A1 Fairy or \(F\) (not just \(-1\) or identifying row); Hag or \(H\) (not just \(\pm 1\) or identifying column)
Robbie should choose the elfB1 Follow through their play-safe for Conan: Elf or \(E\)
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
Dwarf: \(\frac{1}{3}[(-1)+(-4)+(2)] = -1\)M1 \(D = -1\) or \(F = \frac{1}{3}\) or \(-3, 0, 1\)
Elf: \(\frac{1}{3}[(3)+(1)+(-4)] = 0\)
Fairy: \(\frac{1}{3}[(1)+(-1)+(1)] = \frac{1}{3}\)A1 All three correct
Part (iii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
Goblin: \(3p+(1-p)=1+2p\); Hag: \(p-(1-p)=2p-1\); Imp: \(-4p+(1-p)=1-5p\)M1, A1 Any one correct; all three correct (in any form)
\(2p-1=1-5p \Rightarrow p = \frac{2}{7}\)M1, A1 Appropriate equation; \(\frac{2}{7}\) or 0.286 (or better) from method seen
Part (iv)
AnswerMarks Guidance
Answer/WorkingMark Guidance
4 is added throughout the table to make all entries non-negativeB1 Add 4 to remove negative values
If Conan chooses the goblin, expected value (in new table) of \(3x+7y+5z\)B1 Expected value when Conan chooses the goblin
Part (v)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(z = \frac{5}{7} \Rightarrow m \leq 5.571,\ m \leq 3.571,\ m \leq 3.571 \Rightarrow m \leq 3.571\ \left(3\frac{4}{7}\right)\left(\frac{25}{7}\right)\)M1 Using \(z = \frac{5}{7}\) to find a value for \(m\) (or implied)
Hence maximum value for \(M\) is \(3.571 - 4 = -0.429\) or \(-\frac{3}{7}\)M1, A1 Subtracting 4 from their \(m\) value; cao
# Question 5:

## Part (i)

| Answer/Working | Mark | Guidance |
|---|---|---|
| Calculating row minima | M1 | cao |
| Calculating column maxima (or their negatives) | M1 | cao |
| Play-safe for Robbie is fairy; Play-safe for Conan is hag | A1, A1 | Fairy or $F$ (not just $-1$ or identifying row); Hag or $H$ (not just $\pm 1$ or identifying column) |
| Robbie should choose the elf | B1 | Follow through their play-safe for Conan: Elf or $E$ |

## Part (ii)

| Answer/Working | Mark | Guidance |
|---|---|---|
| Dwarf: $\frac{1}{3}[(-1)+(-4)+(2)] = -1$ | M1 | $D = -1$ or $F = \frac{1}{3}$ or $-3, 0, 1$ |
| Elf: $\frac{1}{3}[(3)+(1)+(-4)] = 0$ | | |
| Fairy: $\frac{1}{3}[(1)+(-1)+(1)] = \frac{1}{3}$ | A1 | All three correct |

## Part (iii)

| Answer/Working | Mark | Guidance |
|---|---|---|
| Goblin: $3p+(1-p)=1+2p$; Hag: $p-(1-p)=2p-1$; Imp: $-4p+(1-p)=1-5p$ | M1, A1 | Any one correct; all three correct (in any form) |
| $2p-1=1-5p \Rightarrow p = \frac{2}{7}$ | M1, A1 | Appropriate equation; $\frac{2}{7}$ or 0.286 (or better) from method seen |

## Part (iv)

| Answer/Working | Mark | Guidance |
|---|---|---|
| 4 is added throughout the table to make all entries non-negative | B1 | Add 4 to remove negative values |
| If Conan chooses the goblin, expected value (in new table) of $3x+7y+5z$ | B1 | Expected value when Conan chooses the goblin |

## Part (v)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $z = \frac{5}{7} \Rightarrow m \leq 5.571,\ m \leq 3.571,\ m \leq 3.571 \Rightarrow m \leq 3.571\ \left(3\frac{4}{7}\right)\left(\frac{25}{7}\right)$ | M1 | Using $z = \frac{5}{7}$ to find a value for $m$ (or implied) |
| Hence maximum value for $M$ is $3.571 - 4 = -0.429$ or $-\frac{3}{7}$ | M1, A1 | Subtracting 4 from their $m$ value; cao |

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5 Robbie received a new computer game for Christmas. He has already worked through several levels of the game but is now stuck at one of the levels in which he is playing against a character called Conan. Robbie has played this particular level several times.

Each time Robbie encounters Conan he can choose to be helped by a dwarf, an elf or a fairy. Conan chooses between being helped by a goblin, a hag or an imp. The players make their choices simultaneously, without knowing what the other has chosen.

Robbie starts the level with ten gold coins. The table shows the number of gold coins that Conan must give Robbie in each encounter for each combination of helpers (a negative entry means that Robbie gives gold coins to Conan). If Robbie's total reaches twenty gold coins then he completes the level, but if it reaches zero the game ends. This means that each attempt can be regarded as a zero-sum game.

\begin{center}
\begin{tabular}{ l | l | c | c | c | }
\multicolumn{5}{c}{Conan} \\
\cline { 2 - 5 }
 &  & Goblin & Hag & Imp \\
\cline { 2 - 5 }
 & Dwarf & - 1 & - 4 & 2 \\
\cline { 2 - 5 }
Robbie & Elf & 3 & 1 & - 4 \\
\cline { 2 - 5 }
 & Fairy & 1 & - 1 & 1 \\
\cline { 2 - 5 }
 &  &  &  &  \\
\cline { 2 - 5 }
\end{tabular}
\end{center}

(i) Find the play-safe choice for each player, showing your working. Which helper should Robbie choose if he thinks that Conan will play-safe?\\
(ii) How many gold coins can Robbie expect to win, with each choice of helper, if he thinks that Conan will choose randomly between his three choices (so that each has probability $\frac { 1 } { 3 }$ )?

Robbie decides to choose his helper by using random numbers to choose between the elf and the fairy, where the probability of choosing the elf is $p$ and the probability of choosing the fairy is $1 - p$.\\
(iii) Write down an expression for the expected number of gold coins won at each encounter by Robbie for each of Conan's choices. Calculate the optimal value of $p$.

Robbie's girlfriend thinks that he should have included the possibility of choosing the dwarf. She denotes the probability with which Robbie should choose the dwarf, the elf and the fairy as $x , y$ and $z$ respectively. She then models the problem of choosing between the three helpers as the following LP.

$$\begin{aligned}
\text { Maximise } & M = m - 4 , \\
\text { subject to } & m \leqslant 3 x + 7 y + 5 z \\
& m \leqslant 5 y + 3 z \\
& m \leqslant 6 x + 5 z \\
& x + y + z \leqslant 1 , \\
\text { and } & m \geqslant 0 , x \geqslant 0 , y \geqslant 0 , z \geqslant 0 .
\end{aligned}$$

(iv) Explain how the expression $3 x + 7 y + 5 z$ was formed.

Robbie's girlfriend uses the Simplex algorithm to solve the LP problem. Her solution has $x = 0$ and $y = \frac { 2 } { 7 }$.\\
(v) Calculate the optimal value of $M$.

\hfill \mbox{\textit{OCR D2 2010 Q5 [16]}}