OCR MEI D1 2012 June — Question 4 16 marks

Exam BoardOCR MEI
ModuleD1 (Decision Mathematics 1)
Year2012
SessionJune
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear Programming
TypeGraphical optimization with objective line
DifficultyModerate -0.3 This is a standard linear programming question covering all routine steps: formulating inequalities, graphing the feasible region, and finding optimal solutions using the objective line method. While multi-part with several constraints, it requires only straightforward application of textbook techniques with no novel problem-solving or geometric insight beyond the standard D1 curriculum.
Spec7.06a LP formulation: variables, constraints, objective function7.06b Slack variables: converting inequalities to equations7.06c Working with constraints: algebra and ad hoc methods7.06d Graphical solution: feasible region, two variables

4 In a factory, two types of motor are made. Each motor of type X takes 10 man hours to make and each motor of type Y takes 12 man hours to make. In each week there are 200 man hours available. To satisfy customer demand, at least 5 of each type of motor must be made each week.
Once a motor has been started it must be completed; no unfinished motors may be left in the factory at the end of each week. When completed, the motors are put into a container for shipping. The volume of the container is \(7 \mathrm {~m} ^ { 3 }\). A type X motor occupies a volume of \(0.5 \mathrm {~m} ^ { 3 }\) and a type Y motor occupies a volume of \(0.3 \mathrm {~m} ^ { 3 }\).
  1. Define appropriate variables and from the above information derive four inequalities which must be satisfied by those variables.
  2. Represent your inequalities on a graph and shade the infeasible region. The profit on each type X is \(\pounds 100\) and on each type Y is \(\pounds 70\).
  3. The weekly profit is to be maximised. Write down the objective function and find the maximum profit.
  4. Because of absenteeism, the manager decides to organise the work in the factory on the assumption that there will be only 180 man hours available each week. Find the number of motors of each type that should now be made in order to maximise the profit.

Question 4:
Part (i)
AnswerMarks Guidance
AnswerMarks Guidance
Let \(x\) be the number of type X motors produced. Let \(y\) be the number of type Y motors produced.M1, A1 Adequate definition of "number of". Strict inequalities equally OK.
\(10x + 12y \leq 200\)B1
\(x \geq 5\) and \(y \geq 5\)B1
\(0.5x + 0.3y \leq 7\)B1
[5]
Part (ii)
AnswerMarks Guidance
AnswerMarks Guidance
Inclined lineB1
Inclined lineB1
\(x=5\) and \(y=5\)B1
Shading, follow line errors if shape correctB1 Guidance accuracy throughout is \(\pm 0.25\) on \(x\) and \(\pm 0.25\) on \(y\). Look at \((8,10)\) first. Inaccurate sketch with axis intercepts given is OK.
[4]
Part (iii)
AnswerMarks Guidance
AnswerMarks Guidance
Profit \(= 100X + 70Y\)B1
\((5,12.5)\) or \((5,12)\): 1375 or 1340; \((8,10)\): 1500; \((11,5)\): 1450M1 Optimisation — either profit line or evaluating and comparing at their 3 appropriate points (OK if on graph)
£1500 profitA1 1500 seen cao. SC: B1 for 1500 without the preceding M mark
[3]
Part (iv)
AnswerMarks Guidance
AnswerMarks Guidance
Solution in range \(\left(10 \pm \frac{1}{4},\ 6\frac{2}{3} \pm \frac{1}{4}\right) = \left(9.75\text{–}10.25,\ 6.416\text{–}6.916\right)\)B1 cao — looking for \(\left(10, 6\frac{2}{3}\right)\)
Identification of one of \((9,7)\), \((10,6)\) and \((11,5)\)B1 cao
Evaluation at all three of \((9,7)\): 1390; \((10,6)\): 1420; \((11,5)\): 1450M1
So 11 of X and 5 of YA1 cao
[4]
# Question 4:

## Part (i)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Let $x$ be the number of type X motors produced. Let $y$ be the number of type Y motors produced. | M1, A1 | Adequate definition of "number of". Strict inequalities equally OK. |
| $10x + 12y \leq 200$ | B1 | |
| $x \geq 5$ and $y \geq 5$ | B1 | |
| $0.5x + 0.3y \leq 7$ | B1 | |
| **[5]** | | |

## Part (ii)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Inclined line | B1 | |
| Inclined line | B1 | |
| $x=5$ and $y=5$ | B1 | |
| Shading, follow line errors if shape correct | B1 | Guidance accuracy throughout is $\pm 0.25$ on $x$ and $\pm 0.25$ on $y$. Look at $(8,10)$ first. Inaccurate sketch with axis intercepts given is OK. |
| **[4]** | | |

## Part (iii)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Profit $= 100X + 70Y$ | B1 | |
| $(5,12.5)$ or $(5,12)$: 1375 or 1340; $(8,10)$: 1500; $(11,5)$: 1450 | M1 | Optimisation — either profit line or evaluating and comparing at their 3 appropriate points (OK if on graph) |
| £1500 profit | A1 | 1500 seen cao. SC: B1 for 1500 without the preceding M mark |
| **[3]** | | |

## Part (iv)

| Answer | Marks | Guidance |
|--------|-------|----------|
| Solution in range $\left(10 \pm \frac{1}{4},\ 6\frac{2}{3} \pm \frac{1}{4}\right) = \left(9.75\text{–}10.25,\ 6.416\text{–}6.916\right)$ | B1 | cao — looking for $\left(10, 6\frac{2}{3}\right)$ |
| Identification of one of $(9,7)$, $(10,6)$ and $(11,5)$ | B1 | cao |
| Evaluation at all three of $(9,7)$: 1390; $(10,6)$: 1420; $(11,5)$: 1450 | M1 | |
| So 11 of X and 5 of Y | A1 | cao |
| **[4]** | | |

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4 In a factory, two types of motor are made. Each motor of type X takes 10 man hours to make and each motor of type Y takes 12 man hours to make.

In each week there are 200 man hours available.

To satisfy customer demand, at least 5 of each type of motor must be made each week.\\
Once a motor has been started it must be completed; no unfinished motors may be left in the factory at the end of each week.

When completed, the motors are put into a container for shipping. The volume of the container is $7 \mathrm {~m} ^ { 3 }$. A type X motor occupies a volume of $0.5 \mathrm {~m} ^ { 3 }$ and a type Y motor occupies a volume of $0.3 \mathrm {~m} ^ { 3 }$.\\
(i) Define appropriate variables and from the above information derive four inequalities which must be satisfied by those variables.\\
(ii) Represent your inequalities on a graph and shade the infeasible region.

The profit on each type X is $\pounds 100$ and on each type Y is $\pounds 70$.\\
(iii) The weekly profit is to be maximised. Write down the objective function and find the maximum profit.\\
(iv) Because of absenteeism, the manager decides to organise the work in the factory on the assumption that there will be only 180 man hours available each week. Find the number of motors of each type that should now be made in order to maximise the profit.

\hfill \mbox{\textit{OCR MEI D1 2012 Q4 [16]}}