CAIE FP2 2018 June — Question 11 OR

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2018
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChi-squared goodness of fit
TypeChi-squared goodness of fit: Binomial
DifficultyStandard +0.8 This is a standard chi-squared goodness of fit test with binomial distribution, requiring calculation of sample statistics, verification of expected frequencies using binomial probabilities, and hypothesis testing. While it involves multiple steps and parameter estimation (reducing degrees of freedom), the procedures are routine for Further Maths statistics with no novel problem-solving required. The computational demands and multi-part structure place it slightly above average difficulty.
Spec5.06b Fit prescribed distribution: chi-squared test

A scientist carries out an experiment to investigate the quantity \(X\), which takes the values \(0,1,2,3,4\), 5 or 6 . He believes that the values taken by \(X\) follow a binomial distribution. He conducts 250 trials. His results are summarised in the following table.
\(x\)0123456
Observed frequency228372531730
  1. Show that unbiased estimates of the mean and variance for these results are 1.876 and 1.266 respectively, correct to 3 decimal places. By evaluating the mean and variance of the distribution B(6, 0.313), explain why \(X\) could have this distribution.
    The expected frequencies corresponding to the distribution \(\mathrm { B } ( 6,0.313 )\) are shown in the following table.
    \(x\)0123456
    Observed frequency228372531730
    Expected frequency26.371.981.849.717.03.10.2
  2. Show how the expected frequency for \(x = 4\) is calculated.
  3. Test at the \(5 \%\) significance level whether the scientist's belief is correct.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

A scientist carries out an experiment to investigate the quantity $X$, which takes the values $0,1,2,3,4$, 5 or 6 . He believes that the values taken by $X$ follow a binomial distribution. He conducts 250 trials. His results are summarised in the following table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | c | }
\hline
$x$ & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
Observed frequency & 22 & 83 & 72 & 53 & 17 & 3 & 0 \\
\hline
\end{tabular}
\end{center}

(i) Show that unbiased estimates of the mean and variance for these results are 1.876 and 1.266 respectively, correct to 3 decimal places. By evaluating the mean and variance of the distribution B(6, 0.313), explain why $X$ could have this distribution.\\

The expected frequencies corresponding to the distribution $\mathrm { B } ( 6,0.313 )$ are shown in the following table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | c | }
\hline
$x$ & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
Observed frequency & 22 & 83 & 72 & 53 & 17 & 3 & 0 \\
\hline
Expected frequency & 26.3 & 71.9 & 81.8 & 49.7 & 17.0 & 3.1 & 0.2 \\
\hline
\end{tabular}
\end{center}

(ii) Show how the expected frequency for $x = 4$ is calculated.\\

(iii) Test at the $5 \%$ significance level whether the scientist's belief is correct.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.\\

\hfill \mbox{\textit{CAIE FP2 2018 Q11 OR}}