CAIE FP2 2010 June — Question 2 7 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeRod with end on ground or wall supported by string
DifficultyStandard +0.8 This is a statics problem requiring resolution of forces in two directions, taking moments about a point, and applying friction inequalities. While the setup is standard for Further Maths mechanics, it requires careful geometric reasoning with the angles, systematic application of equilibrium conditions, and understanding that friction provides an inequality constraint rather than a single value. The multi-step nature and the need to find a range for the friction coefficient (not just a single answer) elevates this above routine mechanics questions.
Spec3.04b Equilibrium: zero resultant moment and force

2 A uniform \(\operatorname { rod } A B\) of weight \(W\) rests in equilibrium with \(A\) in contact with a rough vertical wall. The rod is in a vertical plane perpendicular to the wall, and is supported by a force of magnitude \(P\) acting at \(B\) in this vertical plane. The rod makes an angle of \(60 ^ { \circ }\) with the wall, and the force makes an angle of \(30 ^ { \circ }\) with the rod (see diagram). Find the value of \(P\). Find also the set of possible values of the coefficient of friction between the rod and the wall.

Question 2:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(2P\cos 60° = W\sin 60°\)M1 A1 Take moments for rod about \(A\) (A.E.F.)
\(P = W\sqrt{3}/2\) or \(0.866W\)A1 Find \(P\)
\(F = W - P\cos 30° = W/4\)M1 A1\(\sqrt{}\) Resolve vertically for friction \(F\) at \(A\) (\(\sqrt{}\) on \(P\))
\(R = P\sin 30° = W\sqrt{3}/4\) or \(0.433W\)B1\(\sqrt{}\) Resolve horizontally for reaction \(R\) at \(A\) (\(\sqrt{}\) on \(P\))
\(\mu \geq 1/\sqrt{3}\) or \(\mu \geq 0.577\)B1 Use \(F \leq \mu R\) to find values of \(\mu\)
Total: 7 marks
## Question 2:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $2P\cos 60° = W\sin 60°$ | M1 A1 | Take moments for rod about $A$ (A.E.F.) |
| $P = W\sqrt{3}/2$ or $0.866W$ | A1 | Find $P$ |
| $F = W - P\cos 30° = W/4$ | M1 A1$\sqrt{}$ | Resolve vertically for friction $F$ at $A$ ($\sqrt{}$ on $P$) |
| $R = P\sin 30° = W\sqrt{3}/4$ or $0.433W$ | B1$\sqrt{}$ | Resolve horizontally for reaction $R$ at $A$ ($\sqrt{}$ on $P$) |
| $\mu \geq 1/\sqrt{3}$ or $\mu \geq 0.577$ | B1 | Use $F \leq \mu R$ to find values of $\mu$ |

**Total: 7 marks**

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2

A uniform $\operatorname { rod } A B$ of weight $W$ rests in equilibrium with $A$ in contact with a rough vertical wall. The rod is in a vertical plane perpendicular to the wall, and is supported by a force of magnitude $P$ acting at $B$ in this vertical plane. The rod makes an angle of $60 ^ { \circ }$ with the wall, and the force makes an angle of $30 ^ { \circ }$ with the rod (see diagram). Find the value of $P$.

Find also the set of possible values of the coefficient of friction between the rod and the wall.

\hfill \mbox{\textit{CAIE FP2 2010 Q2 [7]}}