CAIE P3 2017 March — Question 4 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionMarch
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard two-part harmonic form question requiring routine application of R cos(θ + α) = R cos α cos θ - R sin α sin θ, followed by solving a transformed equation. The method is well-practiced in P3/C3 courses with no novel insight required, though the double angle (2x) in part (ii) adds a minor complication in finding solutions in the given range. Slightly easier than average due to its predictable structure.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

4
  1. Express \(8 \cos \theta - 15 \sin \theta\) in the form \(R \cos ( \theta + \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\), stating the exact value of \(R\) and giving the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation $$8 \cos 2 x - 15 \sin 2 x = 4$$ for \(0 ^ { \circ } < x < 180 ^ { \circ }\).

Question 4(i):
AnswerMarks Guidance
AnswerMark Guidance
State \(R = 17\)B1
Use trig formula to find \(\alpha\)M1
Obtain \(\alpha = 61.93°\) with no errors seenA1
Total: 3
Question 4(ii):
AnswerMarks Guidance
AnswerMark Guidance
Evaluate \(\cos^{-1}(4/17)\) to at least 1 d.p. (\(76.39°\) to 2 d.p.)B1\(\checkmark\) Follow through mark
Use a correct method to find a value of \(x\) in the interval \(0° < x < 180°\)M1
Obtain answer, e.g. \(x = 7.2°\)A1
Obtain second answer, e.g. \(x = 110.8°\) and no othersA1 Ignore answers outside given interval; treat radians as misread
Total: 4
## Question 4(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $R = 17$ | B1 | |
| Use trig formula to find $\alpha$ | M1 | |
| Obtain $\alpha = 61.93°$ with no errors seen | A1 | |

**Total: 3**

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## Question 4(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Evaluate $\cos^{-1}(4/17)$ to at least 1 d.p. ($76.39°$ to 2 d.p.) | B1$\checkmark$ | Follow through mark |
| Use a correct method to find a value of $x$ in the interval $0° < x < 180°$ | M1 | |
| Obtain answer, e.g. $x = 7.2°$ | A1 | |
| Obtain second answer, e.g. $x = 110.8°$ and no others | A1 | Ignore answers outside given interval; treat radians as misread |

**Total: 4**

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4 (i) Express $8 \cos \theta - 15 \sin \theta$ in the form $R \cos ( \theta + \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$, stating the exact value of $R$ and giving the value of $\alpha$ correct to 2 decimal places.\\

(ii) Hence solve the equation

$$8 \cos 2 x - 15 \sin 2 x = 4$$

for $0 ^ { \circ } < x < 180 ^ { \circ }$.\\

\hfill \mbox{\textit{CAIE P3 2017 Q4 [7]}}