CAIE FP1 2018 June — Question 3 8 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypeArea enclosed by polar curve
DifficultyStandard +0.8 This is a multi-part polar coordinates question requiring sketching a rose curve, applying the polar area formula with integration, and converting to Cartesian form using double-angle identities. While the techniques are standard for Further Maths, the cos 2θ curve requires careful handling of the restricted domain and the integration involves trigonometric manipulation beyond basic A-level, making it moderately challenging.
Spec4.09a Polar coordinates: convert to/from cartesian4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

3 The curve \(C\) has polar equation \(r = \cos 2 \theta\), for \(- \frac { 1 } { 4 } \pi \leqslant \theta \leqslant \frac { 1 } { 4 } \pi\).
  1. Sketch \(C\).
  2. Find the area of the region enclosed by \(C\), showing full working.
  3. Find a cartesian equation of \(C\).

Question 3(i):
AnswerMarks Guidance
AnswerMarks Guidance
Correct position including label of 1 on initial line, symmetric about initial lineB1 Correct position including label of 1 on initial line, and symmetric about initial
Single correct loopB1 Single correct loop
Question 3(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{1}{2}\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \cos^2 2\theta \, d\theta\)M1 Correct integral
\(= \frac{1}{4}\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \cos 4\theta + 1 \, d\theta\)M1 Correct use of double angle formula
\(\frac{1}{4}\left[\frac{1}{4}\sin 4\theta + \theta\right]_{-\frac{\pi}{4}}^{\frac{\pi}{4}} = \frac{\pi}{8} = 0.393\)A1
Question 3(iii):
AnswerMarks Guidance
AnswerMarks Guidance
\(r = \cos^2\theta - \sin^2\theta\) OEB1 Uses trig identity
Thus \(\left(x^2 + y^2\right)^{\frac{3}{2}} = x^2 - y^2\)M1 A1 Uses \(x = r\cos\theta\) or \(y = r\sin\theta\) or both, AEF
## Question 3(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Correct position including label of 1 on initial line, symmetric about initial line | B1 | Correct position including label of 1 on initial line, and symmetric about initial |
| Single correct loop | B1 | Single correct loop |

## Question 3(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{1}{2}\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \cos^2 2\theta \, d\theta$ | M1 | Correct integral |
| $= \frac{1}{4}\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \cos 4\theta + 1 \, d\theta$ | M1 | Correct use of double angle formula |
| $\frac{1}{4}\left[\frac{1}{4}\sin 4\theta + \theta\right]_{-\frac{\pi}{4}}^{\frac{\pi}{4}} = \frac{\pi}{8} = 0.393$ | A1 | |

## Question 3(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $r = \cos^2\theta - \sin^2\theta$ OE | B1 | Uses trig identity |
| Thus $\left(x^2 + y^2\right)^{\frac{3}{2}} = x^2 - y^2$ | M1 A1 | Uses $x = r\cos\theta$ or $y = r\sin\theta$ or both, AEF |
3 The curve $C$ has polar equation $r = \cos 2 \theta$, for $- \frac { 1 } { 4 } \pi \leqslant \theta \leqslant \frac { 1 } { 4 } \pi$.\\
(i) Sketch $C$.\\
(ii) Find the area of the region enclosed by $C$, showing full working.\\

(iii) Find a cartesian equation of $C$.\\

\hfill \mbox{\textit{CAIE FP1 2018 Q3 [8]}}