CAIE P3 2017 June — Question 10 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypePlane containing line and point/vector
DifficultyStandard +0.3 This is a standard Further Maths vectors question requiring finding intersection conditions and plane equations. Part (i) involves setting up parametric equations and solving simultaneously (routine but multi-step). Part (ii) requires finding a plane through two points parallel to a given vector—a textbook application of cross products and normal vectors. Slightly above average difficulty due to the algebraic manipulation required, but follows standard procedures without requiring novel insight.
Spec1.10b Vectors in 3D: i,j,k notation4.04a Line equations: 2D and 3D, cartesian and vector forms4.04b Plane equations: cartesian and vector forms4.04e Line intersections: parallel, skew, or intersecting

10 The points \(A\) and \(B\) have position vectors given by \(\overrightarrow { O A } = \mathbf { i } - 2 \mathbf { j } + 2 \mathbf { k }\) and \(\overrightarrow { O B } = 3 \mathbf { i } + \mathbf { j } + \mathbf { k }\). The line \(l\) has equation \(\mathbf { r } = 2 \mathbf { i } + \mathbf { j } + m \mathbf { k } + \mu ( \mathbf { i } - 2 \mathbf { j } - 4 \mathbf { k } )\), where \(m\) is a constant.
  1. Given that the line \(l\) intersects the line passing through \(A\) and \(B\), find the value of \(m\).
  2. Find the equation of the plane which is parallel to \(\mathbf { i } - 2 \mathbf { j } - 4 \mathbf { k }\) and contains the points \(A\) and \(B\). Give your answer in the form \(a x + b y + c z = d\).

Question 10(i):
AnswerMarks Guidance
AnswerMark Guidance
Carry out a correct method for finding a vector equation for \(AB\)M1
Obtain \(\mathbf{r} = \mathbf{i} - 2\mathbf{j} + 2\mathbf{k} + \lambda(2\mathbf{i} + 3\mathbf{j} - \mathbf{k})\), or equivalentA1
Equate two pairs of components of general points on \(AB\) and \(l\) and solve for \(\lambda\) or \(\mu\)M1
Obtain correct answer for \(\lambda\) or \(\mu\), e.g. \(\lambda = \frac{5}{7}\) or \(\mu = \frac{3}{7}\)A1
Obtain \(m = 3\)A1
Total: 5
Question 10(ii):
AnswerMarks Guidance
AnswerMark Guidance
EITHER: Use scalar product to obtain an equation in \(a\), \(b\) and \(c\), e.g. \(a - 2b - 4c = 0\)B1
Form a second relevant equation, e.g. \(2a + 3b - c = 0\) and solve for one ratio, e.g. \(a:b\)M1
Obtain final answer \(a:b:c = 14:-7:7\)A1
Use coordinates of a relevant point and values of \(a\), \(b\) and \(c\) and find \(d\)M1
Obtain answer \(14x - 7y + 7z = 42\), or equivalentA1
OR 1: Attempt to calculate the vector product of relevant vectors, e.g. \((\mathbf{i} - 2\mathbf{j} - 4\mathbf{k}) \times (2\mathbf{i} + 3\mathbf{j} - \mathbf{k})\)M1
Obtain two correct componentsA1
Obtain correct answer, e.g. \(14\mathbf{i} - 7\mathbf{j} + 7\mathbf{k}\)A1
Substitute coordinates of a relevant point in \(14x - 7y + 7z = d\), or equivalent, and find \(d\)M1
Obtain answer \(14x - 7y + 7z = 42\), or equivalentA1
OR 2: Using a relevant point and relevant vectors, form a 2-parameter equation for the planeM1
State a correct equation, e.g. \(\mathbf{r} = \mathbf{i} - 2\mathbf{j} + 2\mathbf{k} + s(\mathbf{i} - 2\mathbf{j} - 4\mathbf{k}) + t(2\mathbf{i} + 3\mathbf{j} - \mathbf{k})\)A1
State 3 correct equations in \(x\), \(y\), \(z\), \(s\) and \(t\)A1
Eliminate \(s\) and \(t\)M1
Obtain answer \(2x - y + z = 6\), or equivalentA1
OR 3: Using a relevant point and relevant vectors, form a determinant equation for the planeM1
State a correct equation, e.g. \(\begin{vmatrix} x-1 & y+2 & z-1 \\ 1 & -2 & -4 \\ 2 & 3 & -1 \end{vmatrix} = 0\)A1
Attempt to expand the determinantM1
Obtain or imply two correct cofactorsA1
Obtain answer \(14x - 7y + 7z = 42\), or equivalentA1
Total: 5
## Question 10(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| Carry out a correct method for finding a vector equation for $AB$ | M1 | |
| Obtain $\mathbf{r} = \mathbf{i} - 2\mathbf{j} + 2\mathbf{k} + \lambda(2\mathbf{i} + 3\mathbf{j} - \mathbf{k})$, or equivalent | A1 | |
| Equate two pairs of components of general points on $AB$ and $l$ and solve for $\lambda$ or $\mu$ | M1 | |
| Obtain correct answer for $\lambda$ or $\mu$, e.g. $\lambda = \frac{5}{7}$ or $\mu = \frac{3}{7}$ | A1 | |
| Obtain $m = 3$ | A1 | |

**Total: 5**

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## Question 10(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| **EITHER:** Use scalar product to obtain an equation in $a$, $b$ and $c$, e.g. $a - 2b - 4c = 0$ | B1 | |
| Form a second relevant equation, e.g. $2a + 3b - c = 0$ and solve for one ratio, e.g. $a:b$ | M1 | |
| Obtain final answer $a:b:c = 14:-7:7$ | A1 | |
| Use coordinates of a relevant point and values of $a$, $b$ and $c$ and find $d$ | M1 | |
| Obtain answer $14x - 7y + 7z = 42$, or equivalent | A1 | |
| **OR 1:** Attempt to calculate the vector product of relevant vectors, e.g. $(\mathbf{i} - 2\mathbf{j} - 4\mathbf{k}) \times (2\mathbf{i} + 3\mathbf{j} - \mathbf{k})$ | M1 | |
| Obtain two correct components | A1 | |
| Obtain correct answer, e.g. $14\mathbf{i} - 7\mathbf{j} + 7\mathbf{k}$ | A1 | |
| Substitute coordinates of a relevant point in $14x - 7y + 7z = d$, or equivalent, and find $d$ | M1 | |
| Obtain answer $14x - 7y + 7z = 42$, or equivalent | A1 | |
| **OR 2:** Using a relevant point and relevant vectors, form a 2-parameter equation for the plane | M1 | |
| State a correct equation, e.g. $\mathbf{r} = \mathbf{i} - 2\mathbf{j} + 2\mathbf{k} + s(\mathbf{i} - 2\mathbf{j} - 4\mathbf{k}) + t(2\mathbf{i} + 3\mathbf{j} - \mathbf{k})$ | A1 | |
| State 3 correct equations in $x$, $y$, $z$, $s$ and $t$ | A1 | |
| Eliminate $s$ and $t$ | M1 | |
| Obtain answer $2x - y + z = 6$, or equivalent | A1 | |
| **OR 3:** Using a relevant point and relevant vectors, form a determinant equation for the plane | M1 | |
| State a correct equation, e.g. $\begin{vmatrix} x-1 & y+2 & z-1 \\ 1 & -2 & -4 \\ 2 & 3 & -1 \end{vmatrix} = 0$ | A1 | |
| Attempt to expand the determinant | M1 | |
| Obtain or imply two correct cofactors | A1 | |
| Obtain answer $14x - 7y + 7z = 42$, or equivalent | A1 | |

**Total: 5**

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10 The points $A$ and $B$ have position vectors given by $\overrightarrow { O A } = \mathbf { i } - 2 \mathbf { j } + 2 \mathbf { k }$ and $\overrightarrow { O B } = 3 \mathbf { i } + \mathbf { j } + \mathbf { k }$. The line $l$ has equation $\mathbf { r } = 2 \mathbf { i } + \mathbf { j } + m \mathbf { k } + \mu ( \mathbf { i } - 2 \mathbf { j } - 4 \mathbf { k } )$, where $m$ is a constant.\\
(i) Given that the line $l$ intersects the line passing through $A$ and $B$, find the value of $m$.\\

(ii) Find the equation of the plane which is parallel to $\mathbf { i } - 2 \mathbf { j } - 4 \mathbf { k }$ and contains the points $A$ and $B$. Give your answer in the form $a x + b y + c z = d$.\\

\hfill \mbox{\textit{CAIE P3 2017 Q10 [10]}}