OCR FP1 2012 June — Question 9 9 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear transformations
TypeDecompose matrix into transformation sequence
DifficultyStandard +0.8 This is a multi-part Further Maths question requiring recognition of a shear transformation, matrix multiplication to find Y = ZX^(-1), and identification of a composite transformation (rotation + enlargement). While systematic, it demands fluency with matrix operations, inverse matrices, and geometric interpretation of non-standard matrix forms—significantly above average A-level difficulty but standard for FP1.
Spec4.03b Matrix operations: addition, multiplication, scalar4.03d Linear transformations 2D: reflection, rotation, enlargement, shear

9
  1. The matrix \(\mathbf { X }\) is given by \(\mathbf { X } = \left( \begin{array} { l l } 1 & 2 \\ 0 & 1 \end{array} \right)\). Describe fully the geometrical transformation represented by \(\mathbf { X }\).
  2. The matrix \(\mathbf { Z }\) is given by \(\mathbf { Z } = \left( \begin{array} { c c } \frac { 1 } { 2 } & \frac { 1 } { 2 } ( 2 + \sqrt { 3 } ) \\ - \frac { 1 } { 2 } \sqrt { 3 } & \frac { 1 } { 2 } ( 1 - 2 \sqrt { 3 } ) \end{array} \right)\). The transformation represented by \(\mathbf { Z }\) is equivalent to the transformation represented by \(\mathbf { X }\), followed by another transformation represented by the matrix \(\mathbf { Y }\). Find \(\mathbf { Y }\).
  3. Describe fully the geometrical transformation represented by \(\mathbf { Y }\).

Question 9:
Part (i)
AnswerMarks
B1*Shear
depB1e.g. image of \((0, 1)\) is \((2, 1)\) or parallel to the \(x\)-axis
[2]
Part (ii)
Either
AnswerMarks Guidance
B1State \(\mathbf{Z} = \mathbf{YX}\)
B1Obtain \(\mathbf{Y} = \mathbf{ZX}^{-1}\)
\(\begin{pmatrix} 1 & -2 \\ 0 & 1 \end{pmatrix}\)B1 State or use correct inverse
M1Matrix multiplication, 2 elements correct
\(\begin{pmatrix} \frac{1}{2} & \frac{\sqrt{3}}{2} \\ -\frac{\sqrt{3}}{2} & \frac{1}{2} \end{pmatrix}\)A1 Obtain completely correct simplified exact matrix
[5]
Or
AnswerMarks Guidance
\(\mathbf{Z} = \begin{pmatrix} a & b \\ c & d \end{pmatrix}\begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}\)B1 Correct order for matrix multiplication
\(\begin{pmatrix} a & 2a+b \\ c & 2c+d \end{pmatrix}\)B1 Obtain 2 correct elements
B1Obtain other 2 correct elements
M1Equate elements, 2 correct
\(\begin{pmatrix} \frac{1}{2} & \frac{\sqrt{3}}{2} \\ -\frac{\sqrt{3}}{2} & \frac{1}{2} \end{pmatrix}\)A1 Obtain completely correct simplified exact matrix
Part (iii)
AnswerMarks
B1*Rotation
depB1\(60°\) clockwise
[2]
## Question 9:

### Part (i)
| B1* | Shear
| depB1 | e.g. image of $(0, 1)$ is $(2, 1)$ or parallel to the $x$-axis
**[2]**

### Part (ii)
**Either**
| B1 | State $\mathbf{Z} = \mathbf{YX}$
| B1 | Obtain $\mathbf{Y} = \mathbf{ZX}^{-1}$
$\begin{pmatrix} 1 & -2 \\ 0 & 1 \end{pmatrix}$ | B1 | State or use correct inverse
| M1 | Matrix multiplication, 2 elements correct
$\begin{pmatrix} \frac{1}{2} & \frac{\sqrt{3}}{2} \\ -\frac{\sqrt{3}}{2} & \frac{1}{2} \end{pmatrix}$ | A1 | Obtain completely correct simplified exact matrix
**[5]**

**Or**
$\mathbf{Z} = \begin{pmatrix} a & b \\ c & d \end{pmatrix}\begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix}$ | B1 | Correct order for matrix multiplication
$\begin{pmatrix} a & 2a+b \\ c & 2c+d \end{pmatrix}$ | B1 | Obtain 2 correct elements
| B1 | Obtain other 2 correct elements
| M1 | Equate elements, 2 correct
$\begin{pmatrix} \frac{1}{2} & \frac{\sqrt{3}}{2} \\ -\frac{\sqrt{3}}{2} & \frac{1}{2} \end{pmatrix}$ | A1 | Obtain completely correct simplified exact matrix

### Part (iii)
| B1* | Rotation
| depB1 | $60°$ clockwise
**[2]**
9 (i) The matrix $\mathbf { X }$ is given by $\mathbf { X } = \left( \begin{array} { l l } 1 & 2 \\ 0 & 1 \end{array} \right)$. Describe fully the geometrical transformation represented by $\mathbf { X }$.\\
(ii) The matrix $\mathbf { Z }$ is given by $\mathbf { Z } = \left( \begin{array} { c c } \frac { 1 } { 2 } & \frac { 1 } { 2 } ( 2 + \sqrt { 3 } ) \\ - \frac { 1 } { 2 } \sqrt { 3 } & \frac { 1 } { 2 } ( 1 - 2 \sqrt { 3 } ) \end{array} \right)$. The transformation represented by $\mathbf { Z }$ is equivalent to the transformation represented by $\mathbf { X }$, followed by another transformation represented by the matrix $\mathbf { Y }$. Find $\mathbf { Y }$.\\
(iii) Describe fully the geometrical transformation represented by $\mathbf { Y }$.

\hfill \mbox{\textit{OCR FP1 2012 Q9 [9]}}