OCR FP1 2009 January — Question 9 9 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2009
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeInfinite series convergence and sum
DifficultyStandard +0.8 This is a multi-part Further Maths question combining telescoping series (standard FP1 technique) with complex number algebra requiring systematic algebraic manipulation to find square roots, then solving a quartic via substitution, and finally geometric interpretation on an Argand diagram. While each technique is within FP1 scope, the combination of multiple topics, the algebraic complexity of finding exact complex square roots, and the geometric locus work make this moderately challenging for Further Maths students.
Spec4.02h Square roots: of complex numbers4.02i Quadratic equations: with complex roots4.06b Method of differences: telescoping series

9
  1. Show that \(\frac { 1 } { 2 r - 3 } - \frac { 1 } { 2 r + 1 } = \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 }\).
  2. Hence find an expression, in terms of \(n\), for $$\sum _ { r = 2 } ^ { n } \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 }$$
  3. Show that \(\sum _ { r = 2 } ^ { \infty } \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 } = \frac { 4 } { 3 }\).
  4. Use an algebraic method to find the square roots of the complex number \(2 + \mathrm { i } \sqrt { 5 }\). Give your answers in the form \(x + \mathrm { i } y\), where \(x\) and \(y\) are exact real numbers.
  5. Hence find, in the form \(x + \mathrm { i } y\) where \(x\) and \(y\) are exact real numbers, the roots of the equation $$z ^ { 4 } - 4 z ^ { 2 } + 9 = 0$$
  6. Show, on an Argand diagram, the roots of the equation in part (ii).
  7. Given that \(\alpha\) is the root of the equation in part (ii) such that \(0 < \arg \alpha < \frac { 1 } { 2 } \pi\), sketch on the same Argand diagram the locus given by \(| z - \alpha | = | z |\).

Question 9:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Correct denominatorM1 Use correct denominator
Correct answerA1 Obtain given answer correctly
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Express as differences using (i)M1 Express terms as differences using (i)
At least first 3 termsM1 Do this for at least \(1^{\text{st}}\) 3 terms
First 3 terms correctA1 First 3 terms all correct
Last 3 terms correctA1 Last 3 terms all correct (in terms of \(n\) or \(r\))
Pairs cancellingM1 Show pairs cancelling
\(1 + \frac{1}{3} - \frac{1}{2n-1} - \frac{1}{2n+1}\)A1 Obtain correct answer, a.e.f. (in terms of \(n\))
Part (iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{4}{3}\)B1ft Given answer deduced correctly, ft their (ii)
Total: 9 marks
## Question 9:

### Part (i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Correct denominator | M1 | Use correct denominator |
| Correct answer | A1 | Obtain given answer correctly |

### Part (ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Express as differences using (i) | M1 | Express terms as differences using (i) |
| At least first 3 terms | M1 | Do this for at least $1^{\text{st}}$ 3 terms |
| First 3 terms correct | A1 | First 3 terms all correct |
| Last 3 terms correct | A1 | Last 3 terms all correct (in terms of $n$ or $r$) |
| Pairs cancelling | M1 | Show pairs cancelling |
| $1 + \frac{1}{3} - \frac{1}{2n-1} - \frac{1}{2n+1}$ | A1 | Obtain correct answer, a.e.f. (in terms of $n$) |

### Part (iii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{4}{3}$ | B1ft | Given answer deduced correctly, ft their (ii) |

**Total: 9 marks**

---
9 (i) Show that $\frac { 1 } { 2 r - 3 } - \frac { 1 } { 2 r + 1 } = \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 }$.\\
(ii) Hence find an expression, in terms of $n$, for

$$\sum _ { r = 2 } ^ { n } \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 }$$

(iii) Show that $\sum _ { r = 2 } ^ { \infty } \frac { 4 } { 4 r ^ { 2 } - 4 r - 3 } = \frac { 4 } { 3 }$.\\
(i) Use an algebraic method to find the square roots of the complex number $2 + \mathrm { i } \sqrt { 5 }$. Give your answers in the form $x + \mathrm { i } y$, where $x$ and $y$ are exact real numbers.\\
(ii) Hence find, in the form $x + \mathrm { i } y$ where $x$ and $y$ are exact real numbers, the roots of the equation

$$z ^ { 4 } - 4 z ^ { 2 } + 9 = 0$$

(iii) Show, on an Argand diagram, the roots of the equation in part (ii).\\
(iv) Given that $\alpha$ is the root of the equation in part (ii) such that $0 < \arg \alpha < \frac { 1 } { 2 } \pi$, sketch on the same Argand diagram the locus given by $| z - \alpha | = | z |$.

\hfill \mbox{\textit{OCR FP1 2009 Q9 [9]}}