OCR M1 2011 June — Question 1 4 marks

Exam BoardOCR
ModuleM1 (Mechanics 1)
Year2011
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeResultant of coplanar forces
DifficultyEasy -1.8 This is a straightforward application of Pythagoras' theorem and basic trigonometry to find the resultant of two perpendicular forces. It requires only direct recall of standard methods with no problem-solving or conceptual challenge—simpler than typical A-level questions.
Spec3.03p Resultant forces: using vectors
1 Two perpendicular forces have magnitudes 8 N and 15 N . Calculate the magnitude of the resultant force, and the angle which the resultant makes with the larger force.
Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(R = \sqrt{8^2 + 15^2} = \sqrt{289} = 17\) NM1 A1 Use of Pythagoras
\(\tan\theta = \frac{8}{15}\), \(\theta = 28.1°\)M1 A1 Angle with larger (15 N) force 
# Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $R = \sqrt{8^2 + 15^2} = \sqrt{289} = 17$ N | M1 A1 | Use of Pythagoras |
| $\tan\theta = \frac{8}{15}$, $\theta = 28.1°$ | M1 A1 | Angle with larger (15 N) force |

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1 Two perpendicular forces have magnitudes 8 N and 15 N . Calculate the magnitude of the resultant force, and the angle which the resultant makes with the larger force.

\hfill \mbox{\textit{OCR M1 2011 Q1 [4]}}
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Q1 4 Q2 10 Q3 10 Q4 10 Q5 10 Q6 11 Q7 17