Moderate -0.8 This is a straightforward vector addition problem using bearings. Students resolve forces into components (north/east directions are perpendicular, making calculations simple), sum them, then find magnitude using Pythagoras and bearing using inverse tan. It's more routine than average A-level questions since the bearings are along cardinal directions (no awkward angles) and requires only standard mechanics techniques with no problem-solving insight.
1 Three horizontal forces, acting at a single point, have magnitudes \(12 \mathrm {~N} , 14 \mathrm {~N}\) and 5 N and act along bearings \(000 ^ { \circ } , 090 ^ { \circ }\) and \(270 ^ { \circ }\) respectively. Find the magnitude and bearing of their resultant.
1 Three horizontal forces, acting at a single point, have magnitudes $12 \mathrm {~N} , 14 \mathrm {~N}$ and 5 N and act along bearings $000 ^ { \circ } , 090 ^ { \circ }$ and $270 ^ { \circ }$ respectively. Find the magnitude and bearing of their resultant.
\hfill \mbox{\textit{OCR M1 2013 Q1 [5]}}