OCR MEI S4 2013 June — Question 2 24 marks

Exam BoardOCR MEI
ModuleS4 (Statistics 4)
Year2013
SessionJune
Marks24
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoment generating functions
TypeDerive MGF for discrete distribution
DifficultyChallenging +1.8 This is a substantial Further Maths Statistics question requiring MGF derivation, manipulation of MGF properties for linear transformations and sums, Taylor expansion of exponentials, and application of a limit to deduce the Central Limit Theorem. While the individual steps are guided, it requires coordinating multiple advanced techniques across a multi-part proof, placing it well above average difficulty but not at the extreme end for Further Maths content.
Spec5.02b Expectation and variance: discrete random variables5.04a Linear combinations: E(aX+bY), Var(aX+bY)

2 The random variable \(X\) takes values \(- 2,0\) and 2 , each with probability \(\frac { 1 } { 3 }\).
  1. Write down the values of
    (A) \(\mu\), the mean of \(X\),
    (B) \(\mathrm { E } \left( X ^ { 2 } \right)\),
    (C) \(\sigma ^ { 2 }\), the variance of \(X\).
  2. Obtain the moment generating function (mgf) of \(X\). A random sample of \(n\) independent observations on \(X\) has sample mean \(\bar { X }\), and the standardised mean is denoted by \(Z\) where $$Z = \frac { \bar { X } - \mu } { \frac { \sigma } { \sqrt { n } } }$$
  3. Stating carefully the required general results for mgfs of sums and of linear transformations, show that the mgf of \(Z\) is $$M _ { Z } ( \theta ) = \left\{ \frac { 1 } { 3 } \left( 1 + e ^ { \frac { \theta \sqrt { 3 } } { \sqrt { 2 n } } } + e ^ { - \frac { \theta \sqrt { 3 } } { \sqrt { 2 n } } } \right) \right\} ^ { n } .$$
  4. By expanding the exponential functions in \(\mathrm { M } _ { Z } ( \theta )\), show that, for large \(n\), $$\mathrm { M } _ { Z } ( \theta ) \approx \left( 1 + \frac { \theta ^ { 2 } } { 2 n } \right) ^ { n }$$
  5. Use the result \(\mathrm { e } ^ { y } = \lim _ { n \rightarrow \infty } \left( 1 + \frac { y } { n } \right) ^ { n }\) to find the limit of \(\mathrm { M } _ { Z } ( \theta )\) as \(n \rightarrow \infty\), and deduce the approximate distribution of \(Z\) for large \(n\).

2 The random variable $X$ takes values $- 2,0$ and 2 , each with probability $\frac { 1 } { 3 }$.
\begin{enumerate}[label=(\roman*)]
\item Write down the values of\\
(A) $\mu$, the mean of $X$,\\
(B) $\mathrm { E } \left( X ^ { 2 } \right)$,\\
(C) $\sigma ^ { 2 }$, the variance of $X$.
\item Obtain the moment generating function (mgf) of $X$.

A random sample of $n$ independent observations on $X$ has sample mean $\bar { X }$, and the standardised mean is denoted by $Z$ where

$$Z = \frac { \bar { X } - \mu } { \frac { \sigma } { \sqrt { n } } }$$
\item Stating carefully the required general results for mgfs of sums and of linear transformations, show that the mgf of $Z$ is

$$M _ { Z } ( \theta ) = \left\{ \frac { 1 } { 3 } \left( 1 + e ^ { \frac { \theta \sqrt { 3 } } { \sqrt { 2 n } } } + e ^ { - \frac { \theta \sqrt { 3 } } { \sqrt { 2 n } } } \right) \right\} ^ { n } .$$
\item By expanding the exponential functions in $\mathrm { M } _ { Z } ( \theta )$, show that, for large $n$,

$$\mathrm { M } _ { Z } ( \theta ) \approx \left( 1 + \frac { \theta ^ { 2 } } { 2 n } \right) ^ { n }$$
\item Use the result $\mathrm { e } ^ { y } = \lim _ { n \rightarrow \infty } \left( 1 + \frac { y } { n } \right) ^ { n }$ to find the limit of $\mathrm { M } _ { Z } ( \theta )$ as $n \rightarrow \infty$, and deduce the approximate distribution of $Z$ for large $n$.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI S4 2013 Q2 [24]}}