OCR S2 2010 June — Question 5 11 marks

Exam BoardOCR
ModuleS2 (Statistics 2)
Year2010
SessionJune
Marks11
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TopicType I/II errors and power of test
TypeSimultaneous critical region and Type II error
DifficultyChallenging +1.2 This is a multi-part hypothesis testing question requiring standard normal distribution techniques (finding critical regions, Type II error calculations, and power analysis). While it involves several steps and the final part requires algebraic manipulation to find m, all techniques are routine S2 content with no novel insights needed. The computational demands are moderate but straightforward for students who have practiced hypothesis testing.
Spec2.05c Significance levels: one-tail and two-tail2.05e Hypothesis test for normal mean: known variance5.05c Hypothesis test: normal distribution for population mean

5 The time \(T\) seconds needed for a computer to be ready to use, from the moment it is switched on, is a normally distributed random variable with standard deviation 5 seconds. The specification of the computer says that the population mean time should be not more than 30 seconds.
  1. A test is carried out, at the \(5 \%\) significance level, of whether the specification is being met, using the mean \(\bar { t }\) of a random sample of 10 times.
    1. Find the critical region for the test, in terms of \(\bar { t }\).
    2. Given that the population mean time is in fact 35 seconds, find the probability that the test results in a Type II error.
    3. Because of system degradation and memory load, the population mean time \(\mu\) seconds increases with the number of months of use, \(m\). A formula for \(\mu\) in terms of \(m\) is \(\mu = 20 + 0.6 m\). Use this formula to find the value of \(m\) for which the probability that the test results in rejection of the null hypothesis is 0.5 .

5 The time $T$ seconds needed for a computer to be ready to use, from the moment it is switched on, is a normally distributed random variable with standard deviation 5 seconds. The specification of the computer says that the population mean time should be not more than 30 seconds.\\
(i) A test is carried out, at the $5 \%$ significance level, of whether the specification is being met, using the mean $\bar { t }$ of a random sample of 10 times.
\begin{enumerate}[label=(\alph*)]
\item Find the critical region for the test, in terms of $\bar { t }$.
\item Given that the population mean time is in fact 35 seconds, find the probability that the test results in a Type II error.\\
(ii) Because of system degradation and memory load, the population mean time $\mu$ seconds increases with the number of months of use, $m$. A formula for $\mu$ in terms of $m$ is $\mu = 20 + 0.6 m$. Use this formula to find the value of $m$ for which the probability that the test results in rejection of the null hypothesis is 0.5 .
\end{enumerate}

\hfill \mbox{\textit{OCR S2 2010 Q5 [11]}}