OCR MEI S1 2011 June — Question 7

Exam BoardOCR MEI
ModuleS1 (Statistics 1)
Year2011
SessionJune
TopicHypothesis test of binomial distributions
TypeMultiple binomial probability calculations

7 Any patient who fails to turn up for an outpatient appointment at a hospital is described as a 'no-show'. At a particular hospital, on average \(15 \%\) of patients are no-shows. A random sample of 20 patients who have outpatient appointments is selected.
  1. Find the probability that
    (A) there is exactly 1 no-show in the sample,
    (B) there are at least 2 no-shows in the sample. The hospital management introduces a policy of telephoning patients before appointments. It is hoped that this will reduce the proportion of no-shows. In order to check this, a random sample of \(n\) patients is selected. The number of no-shows in the sample is recorded and a hypothesis test is carried out at the 5\% level.
  2. Write down suitable null and alternative hypotheses for the test. Give a reason for your choice of alternative hypothesis.
  3. In the case that \(n = 20\) and the number of no-shows in the sample is 1 , carry out the test.
  4. In another case, where \(n\) is large, the number of no-shows in the sample is 6 and the critical value for the test is 8 . Complete the test.
  5. In the case that \(n \leqslant 18\), explain why there is no point in carrying out the test at the \(5 \%\) level.