OCR C4 2011 January — Question 1 6 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2011
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeComposite substitution expansion
DifficultyModerate -0.3 This is a straightforward two-part binomial expansion question requiring standard application of the formula for (1-x)^(1/2) followed by a substitution x = 2y - 4y². While part (ii) requires recognizing the composite substitution and careful algebraic manipulation to collect terms, this is a routine C4 technique with no novel problem-solving required. Slightly easier than average due to being a standard textbook exercise type.
Spec1.04c Extend binomial expansion: rational n, |x|<1

1
  1. Expand \(( 1 - x ) ^ { \frac { 1 } { 2 } }\) in ascending powers of \(x\) as far as the term in \(x ^ { 2 }\).
  2. Hence expand \(\left( 1 - 2 y + 4 y ^ { 2 } \right) ^ { \frac { 1 } { 2 } }\) in ascending powers of \(y\) as far as the term in \(y ^ { 2 }\).

(i)
AnswerMarks Guidance
\(1 - \frac{1}{2}x\ldots\)B1
Third term = \(\frac{1-(-1)}{2}[(-x)^2 \text{ or } x^2 \text{ or } -x^2]\)M1
\(= -\frac{1}{8}x^2\)A1 3 \(-\frac{1}{8}x^2\) without work \(\to\) M1 A1
(ii)
AnswerMarks Guidance
Attempt to replace \(x\) by \(2y - 4y^2\) or \(2y + 4y^2\)M1 or write as \(1 - (2y - 4y^2 \text{ or } 2y + 4y^2)\)
First two terms are \(1 - y\)B1
Third term = \(+\frac{3}{2}y^2\) or \(\sqrt{(4b+2)y^2}\)A1∇ 3 where \(b = \text{cf}[x^2]\) in part (i)
**(i)**
$1 - \frac{1}{2}x\ldots$ | B1 |
Third term = $\frac{1-(-1)}{2}[(-x)^2 \text{ or } x^2 \text{ or } -x^2]$ | M1 |
$= -\frac{1}{8}x^2$ | A1 3 | $-\frac{1}{8}x^2$ without work $\to$ M1 A1

**(ii)**
Attempt to replace $x$ by $2y - 4y^2$ or $2y + 4y^2$ | M1 | or write as $1 - (2y - 4y^2 \text{ or } 2y + 4y^2)$
First two terms are $1 - y$ | B1 |
Third term = $+\frac{3}{2}y^2$ or $\sqrt{(4b+2)y^2}$ | A1∇ 3 | where $b = \text{cf}[x^2]$ in part (i)

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1 (i) Expand $( 1 - x ) ^ { \frac { 1 } { 2 } }$ in ascending powers of $x$ as far as the term in $x ^ { 2 }$.\\
(ii) Hence expand $\left( 1 - 2 y + 4 y ^ { 2 } \right) ^ { \frac { 1 } { 2 } }$ in ascending powers of $y$ as far as the term in $y ^ { 2 }$.

\hfill \mbox{\textit{OCR C4 2011 Q1 [6]}}