OCR C3 2015 June — Question 3 5 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2015
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeRelated rates with explicitly given non-geometric algebraic relationships
DifficultyStandard +0.3 This is a straightforward related rates problem requiring the chain rule (dV/dt = dV/dh × dh/dt) with one differentiation of a composite function. The setup is clear, the algebra is routine, and it's a standard C3 application question—slightly easier than average due to its direct structure and single-step reasoning.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates

3 The volume, \(V\) cubic metres, of water in a reservoir is given by $$V = 3 ( 2 + \sqrt { h } ) ^ { 6 } - 192 ,$$ where \(h\) metres is the depth of the water. Water is flowing into the reservoir at a constant rate of 150 cubic metres per hour. Find the rate at which the depth of water is increasing at the instant when the depth is 1.4 metres.

Question 3:
AnswerMarks Guidance
AnswerMarks Guidance
Differentiate to obtain \(kh^n(2+\sqrt{h})^5\)M1 Any non-zero constants \(k\), \(n\); condone presence of \(-192\) here
Obtain \(9h^{-\frac{1}{2}}(2+\sqrt{h})^5\) or unsimplified equivA1 Without \(-192\) now
Divide 150 by their derivative, algebraic or numerical\*M1 Using any recognisable attempt at first derivative
Substitute \(h=1.4\) and evaluateM1 Dep \*M; assume appropriate substitution if calculation goes wrong
Obtain \(0.06\) or \(0.060\) or \(0.0603\)A1 But not greater accuracy in final answer; units not needed unless change made to metres and/or hours
[5]
# Question 3:

| Answer | Marks | Guidance |
|--------|-------|----------|
| Differentiate to obtain $kh^n(2+\sqrt{h})^5$ | M1 | Any non-zero constants $k$, $n$; condone presence of $-192$ here |
| Obtain $9h^{-\frac{1}{2}}(2+\sqrt{h})^5$ or unsimplified equiv | A1 | Without $-192$ now |
| Divide 150 by their derivative, algebraic or numerical | \*M1 | Using any recognisable attempt at first derivative |
| Substitute $h=1.4$ and evaluate | M1 | Dep \*M; assume appropriate substitution if calculation goes wrong |
| Obtain $0.06$ or $0.060$ or $0.0603$ | A1 | But not greater accuracy in final answer; units not needed unless change made to metres and/or hours |
| **[5]** | | |

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3 The volume, $V$ cubic metres, of water in a reservoir is given by

$$V = 3 ( 2 + \sqrt { h } ) ^ { 6 } - 192 ,$$

where $h$ metres is the depth of the water. Water is flowing into the reservoir at a constant rate of 150 cubic metres per hour. Find the rate at which the depth of water is increasing at the instant when the depth is 1.4 metres.

\hfill \mbox{\textit{OCR C3 2015 Q3 [5]}}