OCR C2 2010 January — Question 1 6 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2010
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicQuadratic trigonometric equations
TypeShow then solve: sin²/cos² substitution
DifficultyModerate -0.3 This is a standard C2 trigonometric equation requiring the identity sin²x + cos²x = 1 to convert to a quadratic in cos x, then solving using the quadratic formula or factorization. The 'show that' part is routine algebraic manipulation, and solving quadratics in trig functions is a core C2 skill. Slightly easier than average due to the guided structure and straightforward factorization (2cos x - 1)(cos x + 3) = 0.
Spec1.02f Solve quadratic equations: including in a function of unknown1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

1
  1. Show that the equation $$2 \sin ^ { 2 } x = 5 \cos x - 1$$ can be expressed in the form $$2 \cos ^ { 2 } x + 5 \cos x - 3 = 0$$
  2. Hence solve the equation $$2 \sin ^ { 2 } x = 5 \cos x - 1$$ giving all values of \(x\) between \(0 ^ { \circ }\) and \(360 ^ { \circ }\).

1 (i) Show that the equation

$$2 \sin ^ { 2 } x = 5 \cos x - 1$$

can be expressed in the form

$$2 \cos ^ { 2 } x + 5 \cos x - 3 = 0$$

(ii) Hence solve the equation

$$2 \sin ^ { 2 } x = 5 \cos x - 1$$

giving all values of $x$ between $0 ^ { \circ }$ and $360 ^ { \circ }$.

\hfill \mbox{\textit{OCR C2 2010 Q1 [6]}}