CAIE P3 2012 June — Question 4 6 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2012
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeDouble angle with reciprocal functions
DifficultyStandard +0.8 This question requires converting reciprocal trig functions to standard form, applying the double angle formula for sin 2θ, then algebraic manipulation to reach a factorisable equation. While systematic, it demands fluency with multiple identities and careful algebraic handling across several steps, placing it moderately above average difficulty.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

4 Solve the equation $$\operatorname { cosec } 2 \theta = \sec \theta + \cot \theta$$ giving all solutions in the interval \(0 ^ { \circ } < \theta < 360 ^ { \circ }\).

AnswerMarks Guidance
Use trig formulae to express equation in terms of \(\cos\theta\) and \(\sin\theta\)M1
Use Pythagoras to obtain an equation in \(\sin\theta\)M1
Obtain 3-term quadratic \(2\sin^2\theta - 2\sin\theta - 1 = 0\), or equivalentA1
Solve a 3-term quadratic and obtain a value of \(\theta\)M1
Obtain answer, e.g. \(201.5°\)A1
Obtain second answer, e.g. \(338.5°\), and no others in the given intervalA1 [6]
Note: [Ignore answers outside the given interval. Treat answers in radians (3.52, 5.91) as a misread and deduct A1 from the marks for the angles.]
| Use trig formulae to express equation in terms of $\cos\theta$ and $\sin\theta$ | M1 | |
| Use Pythagoras to obtain an equation in $\sin\theta$ | M1 | |
| Obtain 3-term quadratic $2\sin^2\theta - 2\sin\theta - 1 = 0$, or equivalent | A1 | |
| Solve a 3-term quadratic and obtain a value of $\theta$ | M1 | |
| Obtain answer, e.g. $201.5°$ | A1 | |
| Obtain second answer, e.g. $338.5°$, and no others in the given interval | A1 | [6] |

**Note:** [Ignore answers outside the given interval. Treat answers in radians (3.52, 5.91) as a misread and deduct A1 from the marks for the angles.]

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4 Solve the equation

$$\operatorname { cosec } 2 \theta = \sec \theta + \cot \theta$$

giving all solutions in the interval $0 ^ { \circ } < \theta < 360 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P3 2012 Q4 [6]}}