CAIE P3 2020 Specimen — Question 7 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2020
SessionSpecimen
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard harmonic form question requiring expansion of cos(x+30°), combining terms into Rcos(x+α) form, then solving a straightforward equation. While it involves multiple steps, the techniques are routine for P3 level with no novel insight required—slightly easier than average due to its predictable structure.
Spec1.05l Double angle formulae: and compound angle formulae1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc

7
  1. By first expanding \(\cos \left( x + 45 ^ { \circ } \right)\), express \(\cos \left( x + 45 ^ { \circ } \right) - \sqrt { 2 } \sin x\) in the form \(R \cos ( x + \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\). Give the value of \(R\) correct to 4 significant figures and the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation $$\cos \left( x + 45 ^ { \circ } \right) - \sqrt { 2 } \sin x = 2$$ for \(0 ^ { \circ } < x < 360 ^ { \circ }\).

Question 7:
Part 7(a):
AnswerMarks Guidance
AnswerMark Guidance
Use \(\cos(A+B)\) formula to obtain expression in terms of \(\cos x\) and \(\sin x\)M1
Collect terms and reach \(\frac{\cos x}{\sqrt{2}} - \frac{3}{\sqrt{2}}\sin x\), or equivalentA1
Obtain \(R = 2.236\)A1
Use trig formula to find \(\alpha\)M1
Obtain \(\alpha = 71.57°\) with no errors seenA1
Total5
Part 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Evaluate \(\cos^{-1}\left(\frac{2}{2.236}\right)\) to at least 1 dpB1FT
Carry out appropriate method to find a value of \(x\) in the interval \(0° < x < 360°\)M1
Obtain answer, e.g. \(x = 315°\)A1
Obtain second answer, e.g. \(261.9°\) and no others in the given intervalA1
Total4
# Question 7:

## Part 7(a):
| Answer | Mark | Guidance |
|--------|------|----------|
| Use $\cos(A+B)$ formula to obtain expression in terms of $\cos x$ and $\sin x$ | M1 | |
| Collect terms and reach $\frac{\cos x}{\sqrt{2}} - \frac{3}{\sqrt{2}}\sin x$, or equivalent | A1 | |
| Obtain $R = 2.236$ | A1 | |
| Use trig formula to find $\alpha$ | M1 | |
| Obtain $\alpha = 71.57°$ with no errors seen | A1 | |
| **Total** | **5** | |

## Part 7(b):
| Answer | Mark | Guidance |
|--------|------|----------|
| Evaluate $\cos^{-1}\left(\frac{2}{2.236}\right)$ to at least 1 dp | B1FT | |
| Carry out appropriate method to find a value of $x$ in the interval $0° < x < 360°$ | M1 | |
| Obtain answer, e.g. $x = 315°$ | A1 | |
| Obtain second answer, e.g. $261.9°$ and no others in the given interval | A1 | |
| **Total** | **4** | |

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7 (a) By first expanding $\cos \left( x + 45 ^ { \circ } \right)$, express $\cos \left( x + 45 ^ { \circ } \right) - \sqrt { 2 } \sin x$ in the form $R \cos ( x + \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$. Give the value of $R$ correct to 4 significant figures and the value of $\alpha$ correct to 2 decimal places.\\
(b) Hence solve the equation

$$\cos \left( x + 45 ^ { \circ } \right) - \sqrt { 2 } \sin x = 2$$

for $0 ^ { \circ } < x < 360 ^ { \circ }$.\\

\hfill \mbox{\textit{CAIE P3 2020 Q7 [9]}}