CAIE P1 2023 March — Question 11 11 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2023
SessionMarch
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeRotation about y-axis, region between two curves
DifficultyChallenging +1.2 This is a multi-step volumes of revolution question requiring finding a line equation, then computing volume between curve and line rotated about y-axis. While it involves several techniques (line equation, integration with limits, difference of volumes), the setup is straightforward with clearly marked points and standard methods. The integration itself (polynomials) is routine. Slightly above average due to the multi-part nature and rotation about y-axis (less common than x-axis), but no novel insight required.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=04.08d Volumes of revolution: about x and y axes

11 \includegraphics[max width=\textwidth, alt={}, center]{3bad1d9f-5b9e-4895-aa4e-3e6d9f6c072e-16_599_780_274_671} The diagram shows the curve with equation \(x = y ^ { 2 } + 1\). The points \(A ( 5,2 )\) and \(B ( 2 , - 1 )\) lie on the curve.
  1. Find an equation of the line \(A B\).
  2. Find the volume of revolution when the region between the curve and the line \(A B\) is rotated through \(360 ^ { \circ }\) about the \(\boldsymbol { y }\)-axis.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 11:
Part 11(a):
AnswerMarks Guidance
Gradient of \(AB = \frac{2-(-1)}{5-2}\)M1 Expect 1, must be from \(\Delta y / \Delta x\)
Equation of \(AB\) is \(y - 2 = 1(x-5)\) or \(y + 1 = 1(x-2)\)A1 OE. Expect \(y = x - 3\)
Part 11(b):
AnswerMarks Guidance
\([\pi]\int x^2\,dy = [\pi]\int(y^2+1)^2\,dy = [\pi]\int(y^4+2y^2+1)\,dy\)M1 For curve: attempt to square \(y^2+1\) and attempt integration. Subtracting curve equation from line equation before squaring is M0. Integration before squaring is M0
\([\pi]\left(\frac{y^5}{5} + \frac{2y^3}{3} + y\right)\)A2, 1, 0
\([\pi]\int(y+3)^2\,dy = [\pi]\int(y^2+6y+9)\,dy\)M1 For line: attempt to square *their* \(y+3\) and attempt integration
\([\pi]\left(\frac{y^3}{3} + 3y^2 + 9y\right)\) or \([\pi]\left(\frac{(y+3)^3}{3}\right)\)A2, 1, 0 Not available for incorrect line equations
\([\pi]\left\{\frac{8}{3}+12+18-\left(-\frac{1}{3}+3-9\right)\right\}\) or \([\pi]\left\{\frac{32}{5}+\frac{16}{3}+2-\left(-\frac{1}{5}-\frac{2}{3}-1\right)\right\}\)DM1 Apply limits \(-1 \to 2\) to either integral. Expect \(15\frac{3}{5}[\pi]\) and/or \(39[\pi]\). Evidence of substitution of both \(-1\) and \(2\) must be seen. Dependent on at least one of first 2 M1 marks
Volume \(= [\pi]\left(39 - 15\frac{3}{5}\right)\)DM1 Appropriate subtraction. Dependent on at least one of first 2 M1 marks
\(= 23\frac{2}{5}\pi\) or \(\frac{117}{5}\pi\) or awrt \(73.5[1327]\)A1
## Question 11:

**Part 11(a):**
| Gradient of $AB = \frac{2-(-1)}{5-2}$ | M1 | Expect 1, must be from $\Delta y / \Delta x$ |
| Equation of $AB$ is $y - 2 = 1(x-5)$ or $y + 1 = 1(x-2)$ | A1 | OE. Expect $y = x - 3$ |

**Part 11(b):**
| $[\pi]\int x^2\,dy = [\pi]\int(y^2+1)^2\,dy = [\pi]\int(y^4+2y^2+1)\,dy$ | M1 | For curve: attempt to square $y^2+1$ and attempt integration. Subtracting curve equation from line equation before squaring is M0. Integration before squaring is M0 |
| $[\pi]\left(\frac{y^5}{5} + \frac{2y^3}{3} + y\right)$ | A2, 1, 0 | |
| $[\pi]\int(y+3)^2\,dy = [\pi]\int(y^2+6y+9)\,dy$ | M1 | For line: attempt to square *their* $y+3$ and attempt integration |
| $[\pi]\left(\frac{y^3}{3} + 3y^2 + 9y\right)$ or $[\pi]\left(\frac{(y+3)^3}{3}\right)$ | A2, 1, 0 | Not available for incorrect line equations |
| $[\pi]\left\{\frac{8}{3}+12+18-\left(-\frac{1}{3}+3-9\right)\right\}$ or $[\pi]\left\{\frac{32}{5}+\frac{16}{3}+2-\left(-\frac{1}{5}-\frac{2}{3}-1\right)\right\}$ | DM1 | Apply limits $-1 \to 2$ to either integral. Expect $15\frac{3}{5}[\pi]$ and/or $39[\pi]$. Evidence of substitution of both $-1$ and $2$ must be seen. Dependent on at least one of first 2 M1 marks |
| Volume $= [\pi]\left(39 - 15\frac{3}{5}\right)$ | DM1 | Appropriate subtraction. Dependent on at least one of first 2 M1 marks |
| $= 23\frac{2}{5}\pi$ or $\frac{117}{5}\pi$ or awrt $73.5[1327]$ | A1 | |
11\\
\includegraphics[max width=\textwidth, alt={}, center]{3bad1d9f-5b9e-4895-aa4e-3e6d9f6c072e-16_599_780_274_671}

The diagram shows the curve with equation $x = y ^ { 2 } + 1$. The points $A ( 5,2 )$ and $B ( 2 , - 1 )$ lie on the curve.
\begin{enumerate}[label=(\alph*)]
\item Find an equation of the line $A B$.
\item Find the volume of revolution when the region between the curve and the line $A B$ is rotated through $360 ^ { \circ }$ about the $\boldsymbol { y }$-axis.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2023 Q11 [11]}}