CAIE P3 2006 June — Question 4

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2006
SessionJune
TopicHarmonic Form

4
  1. Express \(7 \cos \theta + 24 \sin \theta\) in the form \(R \cos ( \theta - \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\), giving the exact value of \(R\) and the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation $$7 \cos \theta + 24 \sin \theta = 15$$ giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).