CAIE P2 2018 June — Question 4 7 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2018
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeSolve log equation then substitute trig/exponential expression
DifficultyStandard +0.3 Part (i) is a standard logarithm equation requiring application of log laws (power rule, subtraction rule) to form a quadratic, which is routine A-level material. Part (ii) adds a substitution step (recognizing 2^u = x) but is straightforward once part (i) is solved. The question requires multiple techniques but follows predictable patterns with no novel insight needed, making it slightly easier than average.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

4
  1. Solve the equation \(2 \ln ( 2 x ) - \ln ( x + 3 ) = 4 \ln 2\).
  2. Hence solve the equation $$2 \ln \left( 2 ^ { u + 1 } \right) - \ln \left( 2 ^ { u } + 3 \right) = 4 \ln 2$$ giving the value of \(u\) correct to 4 significant figures.

Question 4(i):
AnswerMarks Guidance
AnswerMarks Guidance
Use \(2\ln(2x) = \ln(4x^2)\)B1
Use law for addition or subtraction of logarithmsM1
Obtain correct equation \(\frac{4x^2}{x+3} = 16\) or equivalentA1 With no logarithms involved
Solve 3-term quadratic equationM1 Dependent on previous M1
Conclude with \(x = 6\) and, finally, no other solutionsA1
Question 4(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Apply logarithms and use power law for \(2^a = k\) or \(2^{a+1} = 2k\) where \(k > 0\)M1
Obtain 2.585A1
## Question 4(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use $2\ln(2x) = \ln(4x^2)$ | B1 | |
| Use law for addition or subtraction of logarithms | M1 | |
| Obtain correct equation $\frac{4x^2}{x+3} = 16$ or equivalent | A1 | With no logarithms involved |
| Solve 3-term quadratic equation | M1 | Dependent on previous M1 |
| Conclude with $x = 6$ and, finally, no other solutions | A1 | |

## Question 4(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Apply logarithms and use power law for $2^a = k$ or $2^{a+1} = 2k$ where $k > 0$ | M1 | |
| Obtain 2.585 | A1 | |
4 (i) Solve the equation $2 \ln ( 2 x ) - \ln ( x + 3 ) = 4 \ln 2$.\\

(ii) Hence solve the equation

$$2 \ln \left( 2 ^ { u + 1 } \right) - \ln \left( 2 ^ { u } + 3 \right) = 4 \ln 2$$

giving the value of $u$ correct to 4 significant figures.\\

\hfill \mbox{\textit{CAIE P2 2018 Q4 [7]}}