CAIE P2 2016 June — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2016
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeProve identity then solve equation only (no integral)
DifficultyStandard +0.3 This is a straightforward application of addition formulae requiring expansion of sin(θ+60°) and sin(θ+120°), simplification using exact values, then two routine applications. Part (ii)(a) is direct substitution, and (ii)(b) is a standard trigonometric equation. The multi-step nature and exact value work place it slightly above average, but all techniques are standard P2 material with no novel insight required.
Spec1.05g Exact trigonometric values: for standard angles1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

4
  1. Show that \(\sin \left( \theta + 60 ^ { \circ } \right) + \sin \left( \theta + 120 ^ { \circ } \right) \equiv ( \sqrt { } 3 ) \cos \theta\).
  2. Hence
    1. find the exact value of \(\sin 105 ^ { \circ } + \sin 165 ^ { \circ }\),
    2. solve the equation \(\sin \left( \theta + 60 ^ { \circ } \right) + \sin \left( \theta + 120 ^ { \circ } \right) = \sec \theta\) for \(0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }\).

Question 4:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State \(\sin\theta\cos 60 + \cos\theta\sin 60 + \sin\theta\cos 120 + \cos\theta\sin 120\)*B1
Use \(\sin 60 = \sin 120 = \frac{1}{2}\sqrt{3}\) and \(\cos 60 = \frac{1}{2}\), \(\cos 120 = -\frac{1}{2}\)*B1
Confirm result \(\sqrt{3}\cos\theta\), dependent on *B *BDB1 [3]
Part (ii)(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\cos 45\) seen*B1
State \(\sqrt{\frac{3}{2}}\) or \(\frac{1}{2}\sqrt{6}\) or exact equivalent, dependent *BDB1 [2]
Part (ii)(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Carry out correct process to find at least one value of \(\theta\) from \(\cos^2\theta = k\)M1
Obtain 40.6A1
Obtain 139.4A1 [3]
## Question 4:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State $\sin\theta\cos 60 + \cos\theta\sin 60 + \sin\theta\cos 120 + \cos\theta\sin 120$ | *B1 | |
| Use $\sin 60 = \sin 120 = \frac{1}{2}\sqrt{3}$ and $\cos 60 = \frac{1}{2}$, $\cos 120 = -\frac{1}{2}$ | *B1 | |
| Confirm result $\sqrt{3}\cos\theta$, dependent on *B *B | DB1 | [3] |

### Part (ii)(a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\cos 45$ seen | *B1 | |
| State $\sqrt{\frac{3}{2}}$ or $\frac{1}{2}\sqrt{6}$ or exact equivalent, dependent *B | DB1 | [2] |

### Part (ii)(b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Carry out correct process to find at least one value of $\theta$ from $\cos^2\theta = k$ | M1 | |
| Obtain 40.6 | A1 | |
| Obtain 139.4 | A1 | [3] |

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4 (i) Show that $\sin \left( \theta + 60 ^ { \circ } \right) + \sin \left( \theta + 120 ^ { \circ } \right) \equiv ( \sqrt { } 3 ) \cos \theta$.\\
(ii) Hence
\begin{enumerate}[label=(\alph*)]
\item find the exact value of $\sin 105 ^ { \circ } + \sin 165 ^ { \circ }$,
\item solve the equation $\sin \left( \theta + 60 ^ { \circ } \right) + \sin \left( \theta + 120 ^ { \circ } \right) = \sec \theta$ for $0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2016 Q4 [8]}}