OCR C3 — Question 5 9 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeShow equation reduces to tan form
DifficultyStandard +0.8 This question requires multiple sophisticated steps: expanding sec(x + π/6) using addition formulae, algebraic manipulation to reach the target form, then solving a trigonometric equation that requires factoring or converting to tan form. While the techniques are C3 standard, the multi-step manipulation and non-obvious path from the given to target form makes this moderately harder than average.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

  1. (i) Show that the equation
$$2 \sin x + \sec \left( x + \frac { \pi } { 6 } \right) = 0$$ can be written as $$\sqrt { 3 } \sin x \cos x + \cos ^ { 2 } x = 0$$ (ii) Hence, or otherwise, find in terms of \(\pi\) the solutions of the equation $$2 \sin x + \sec \left( x + \frac { \pi } { 6 } \right) = 0$$ for \(x\) in the interval \(0 \leq x \leq \pi\).

\begin{enumerate}
  \item (i) Show that the equation
\end{enumerate}

$$2 \sin x + \sec \left( x + \frac { \pi } { 6 } \right) = 0$$

can be written as

$$\sqrt { 3 } \sin x \cos x + \cos ^ { 2 } x = 0$$

(ii) Hence, or otherwise, find in terms of $\pi$ the solutions of the equation

$$2 \sin x + \sec \left( x + \frac { \pi } { 6 } \right) = 0$$

for $x$ in the interval $0 \leq x \leq \pi$.\\

\hfill \mbox{\textit{OCR C3  Q5 [9]}}