Edexcel M3 2012 January — Question 2 8 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2012
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimple Harmonic Motion
TypeSpeed at given displacement
DifficultyStandard +0.3 This is a straightforward SHM question requiring standard formula application: finding ω from period, then using a = -ω²x for acceleration and v² = ω²(a² - x²) for speed, plus basic time calculation. All steps are routine M3 techniques with no conceptual challenges or novel problem-solving required, making it slightly easier than average.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x

2. A particle \(P\) is moving in a straight line with simple harmonic motion. The centre of the oscillation is the fixed point \(C\), the amplitude of the oscillation is 0.5 m and the time to complete one oscillation is \(\frac { 2 \pi } { 3 }\) seconds. The point \(A\) is on the path of \(P\) and 0.2 m from \(C\). Find
  1. the magnitude and direction of the acceleration of \(P\) when it passes through \(A\),
  2. the speed of \(P\) when it passes through \(A\),
  3. the time \(P\) takes to move directly from \(C\) to \(A\).

Question 2:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(T = \frac{2\pi}{\omega} = \frac{2\pi}{3}\), \(\omega = 3\)B1
\(a = \omega^2 x = 9 \times 0.2 = 1.8 \text{ ms}^{-2}\) towards \(C\)
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(v^2 = \omega^2(a^2 - x^2) = 9(0.25 - 0.04) = 1.89\)M1
\(v = 1.37 \text{ ms}^{-1}\)A1 (2)
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x = 0.5\sin 3t = 0.2\)M1 A1ft
\(t = \frac{1}{3}\sin^{-1} 0.4 \approx 0.137 \text{ s}\)A1 (3) Total: 8
## Question 2:

### Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $T = \frac{2\pi}{\omega} = \frac{2\pi}{3}$, $\omega = 3$ | B1 | |
| $|a| = \omega^2 x = 9 \times 0.2 = 1.8 \text{ ms}^{-2}$ towards $C$ | M1 A1 | (3) |

### Part (b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $v^2 = \omega^2(a^2 - x^2) = 9(0.25 - 0.04) = 1.89$ | M1 | |
| $v = 1.37 \text{ ms}^{-1}$ | A1 | (2) |

### Part (c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $x = 0.5\sin 3t = 0.2$ | M1 A1ft | |
| $t = \frac{1}{3}\sin^{-1} 0.4 \approx 0.137 \text{ s}$ | A1 | (3) Total: 8 |

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2. A particle $P$ is moving in a straight line with simple harmonic motion. The centre of the oscillation is the fixed point $C$, the amplitude of the oscillation is 0.5 m and the time to complete one oscillation is $\frac { 2 \pi } { 3 }$ seconds. The point $A$ is on the path of $P$ and 0.2 m from $C$. Find
\begin{enumerate}[label=(\alph*)]
\item the magnitude and direction of the acceleration of $P$ when it passes through $A$,
\item the speed of $P$ when it passes through $A$,
\item the time $P$ takes to move directly from $C$ to $A$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3 2012 Q2 [8]}}