CAIE P1 2021 March — Question 6 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2021
SessionMarch
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind curve equation from derivative (reverse chain rule / composite functions)
DifficultyModerate -0.3 Part (a) requires straightforward application of the chain rule dy/dt = (dy/dx)(dx/dt) with given values. Part (b) is a standard reverse chain rule integration to find y, using the boundary condition to find the constant. Both parts are routine A-level techniques with no novel problem-solving required, making this slightly easier than average.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.08a Fundamental theorem of calculus: integration as reverse of differentiation

6 A curve is such that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 6 } { ( 3 x - 2 ) ^ { 3 } }\) and \(A ( 1 , - 3 )\) lies on the curve. A point is moving along the curve and at \(A\) the \(y\)-coordinate of the point is increasing at 3 units per second.
  1. Find the rate of increase at \(A\) of the \(x\)-coordinate of the point.
  2. Find the equation of the curve.

Question 6:
AnswerMarks Guidance
AnswerMarks Guidance
(a) At \(x = 1\), \(\frac{dy}{dx} = 6\)B1
(a) \(\frac{dx}{dt} = \left(\frac{dx}{dy} \times \frac{dy}{dt}\right) = \frac{1}{6} \times 3 = \frac{1}{2}\)M1 A1 Chain rule used correctly. Allow alternative and minimal notation
(b) \([y =]\ \left(\frac{6(3x-2)^{-2}}{-2}\right) \div (3)\ [+c]\)B1 B1
(b) \(-3 = -1 + c\)M1 Substitute \(x = 1\), \(y = -3\). \(c\) must be present
(b) \(y = -(3x-2)^{-2} - 2\)A1 OE. Allow \(f(x) =\)
## Question 6:

| Answer | Marks | Guidance |
|--------|-------|----------|
| (a) At $x = 1$, $\frac{dy}{dx} = 6$ | B1 | |
| (a) $\frac{dx}{dt} = \left(\frac{dx}{dy} \times \frac{dy}{dt}\right) = \frac{1}{6} \times 3 = \frac{1}{2}$ | M1 A1 | Chain rule used correctly. Allow alternative and minimal notation |
| (b) $[y =]\ \left(\frac{6(3x-2)^{-2}}{-2}\right) \div (3)\ [+c]$ | B1 B1 | |
| (b) $-3 = -1 + c$ | M1 | Substitute $x = 1$, $y = -3$. $c$ must be present |
| (b) $y = -(3x-2)^{-2} - 2$ | A1 | OE. Allow $f(x) =$ |

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6 A curve is such that $\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 6 } { ( 3 x - 2 ) ^ { 3 } }$ and $A ( 1 , - 3 )$ lies on the curve. A point is moving along the curve and at $A$ the $y$-coordinate of the point is increasing at 3 units per second.
\begin{enumerate}[label=(\alph*)]
\item Find the rate of increase at $A$ of the $x$-coordinate of the point.
\item Find the equation of the curve.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2021 Q6 [7]}}