| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2017 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Impulse and momentum (advanced) |
| Type | Impulse from velocity change |
| Difficulty | Moderate -0.8 This is a straightforward application of the impulse-momentum theorem (I = mv - mu) with vector components. It requires basic vector arithmetic and finding magnitude/angle, which are standard M2 techniques with no problem-solving insight needed. Simpler than average A-level questions due to its direct plug-and-calculate nature. |
| Spec | 6.03f Impulse-momentum: relation6.03g Impulse in 2D: vector form |
\begin{enumerate}
\item A particle $P$ of mass 0.5 kg is moving with velocity $4 \mathbf { j } \mathrm {~m} \mathrm {~s} ^ { - 1 }$ when it receives an impulse I Ns. Immediately after $P$ receives the impulse, the velocity of $P$ is $( 2 \mathbf { i } + 3 \mathbf { j } ) \mathrm { ms } ^ { - 1 }$.
\end{enumerate}
Find\\
(a) the magnitude of $\mathbf { I }$,\\
(b) the angle between $\mathbf { I }$ and $\mathbf { j }$.\\
\hfill \mbox{\textit{Edexcel M2 2017 Q1 [6]}}