Edexcel M2 2004 January — Question 1 5 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2004
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind power at constant speed
DifficultyModerate -0.3 This is a straightforward application of the power equation P = Fv at constant speed, where forces balance. Students must resolve forces parallel to the incline (weight component + resistance = driving force) and substitute into the power formula. It's a standard M2 exercise requiring routine application of well-practiced techniques with no conceptual surprises, making it slightly easier than average.
Spec6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

  1. A car of mass 400 kg is moving up a straight road inclined at an angle \(\theta\) to the horizontal, where \(\sin \theta = \frac { 1 } { 14 }\). The resistance to motion of the car from non-gravitational forces is modelled as a constant force of magnitude \(R\) newtons. When the car is moving at a constant speed of \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\), the power developed by the car's engine is 10 kW .
Find the value of \(R\).

\begin{enumerate}
  \item A car of mass 400 kg is moving up a straight road inclined at an angle $\theta$ to the horizontal, where $\sin \theta = \frac { 1 } { 14 }$. The resistance to motion of the car from non-gravitational forces is modelled as a constant force of magnitude $R$ newtons. When the car is moving at a constant speed of $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, the power developed by the car's engine is 10 kW .
\end{enumerate}

Find the value of $R$.\\

\hfill \mbox{\textit{Edexcel M2 2004 Q1 [5]}}