Edexcel M2 2018 October — Question 2 9 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2018
SessionOctober
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeEnergy method - driving force up incline, find work done by engine/force
DifficultyStandard +0.3 This is a straightforward M2 work-energy question requiring standard application of the work-energy principle with resistance forces and an incline, followed by a routine power-force-acceleration calculation. Both parts use well-practiced techniques with no novel problem-solving required, making it slightly easier than average.
Spec6.02d Mechanical energy: KE and PE concepts6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

2. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{99d06f7b-f5cc-4c19-ae26-8f715eda8ee8-04_442_810_237_557} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} A truck of mass 1200 kg is being driven up a straight road that is inclined at an angle \(\alpha\) to the horizontal, where \(\sin \alpha = \frac { 1 } { 15 }\). The resistance to the motion of the truck from non-gravitational forces is modelled as a single constant force of magnitude 250 N . Two points, \(A\) and \(B\), lie on the road, with \(A B = 90 \mathrm {~m}\). The speed of the truck at \(A\) is \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the speed of the truck at \(B\) is \(8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\), as shown in Figure 2. The truck is modelled as a particle and the road is modelled as a straight line.
  1. Find the work done by the engine of the truck as the truck moves from \(A\) to \(B\). On another occasion, the truck is being driven down the same road. The resistance to the motion of the truck is modelled as a single constant force of magnitude 250 N . The engine of the truck is working at a constant rate of 8 kW .
  2. Find the acceleration of the truck at the instant when its speed is \(6 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).

2.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{99d06f7b-f5cc-4c19-ae26-8f715eda8ee8-04_442_810_237_557}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

A truck of mass 1200 kg is being driven up a straight road that is inclined at an angle $\alpha$ to the horizontal, where $\sin \alpha = \frac { 1 } { 15 }$. The resistance to the motion of the truck from non-gravitational forces is modelled as a single constant force of magnitude 250 N . Two points, $A$ and $B$, lie on the road, with $A B = 90 \mathrm {~m}$. The speed of the truck at $A$ is $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and the speed of the truck at $B$ is $8 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, as shown in Figure 2.

The truck is modelled as a particle and the road is modelled as a straight line.
\begin{enumerate}[label=(\alph*)]
\item Find the work done by the engine of the truck as the truck moves from $A$ to $B$.

On another occasion, the truck is being driven down the same road. The resistance to the motion of the truck is modelled as a single constant force of magnitude 250 N . The engine of the truck is working at a constant rate of 8 kW .
\item Find the acceleration of the truck at the instant when its speed is $6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2018 Q2 [9]}}