| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2023 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Impulse and momentum (advanced) |
| Type | Impulse from velocity change |
| Difficulty | Moderate -0.3 This is a straightforward application of the impulse-momentum theorem (I = mv - mu) with vector components. Part (a) requires basic vector arithmetic and magnitude calculation, while part (b) needs a dot product or component angle calculation. Standard M2 material with no conceptual challenges beyond routine application of formulas. |
| Spec | 6.03e Impulse: by a force6.03f Impulse-momentum: relation |
\begin{enumerate}
\item A particle $P$ of mass 0.3 kg is moving with velocity $5 \mathbf { i } \mathrm {~m} \mathrm {~s} ^ { - 1 }$
\end{enumerate}
The particle receives an impulse I Ns.\\
Immediately after receiving the impulse, the velocity of $P$ is $( 7 \mathbf { i } + 7 \mathbf { j } ) \mathrm { ms } ^ { - 1 }$\\
(a) Find the magnitude of $\mathbf { I }$\\
(b) Find the angle between the direction of $\mathbf { I }$ and the direction of motion of $P$ immediately before receiving the impulse.
\hfill \mbox{\textit{Edexcel M2 2023 Q1 [7]}}