Edexcel M2 2021 June — Question 3 8 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2021
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeLamina hinged at point with string support
DifficultyStandard +0.3 This is a standard M2 moments question requiring center of mass calculation for a composite lamina (using subtraction of shapes) and then equilibrium with two vertical strings. The geometry is clearly specified, the method is routine (take moments about shapes, then about a point for equilibrium), and it's a typical textbook exercise with straightforward arithmetic. Slightly easier than average due to clear setup and standard technique application.
Spec6.04c Composite bodies: centre of mass6.04d Integration: for centre of mass of laminas/solids6.04e Rigid body equilibrium: coplanar forces

3. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{e6e37d85-f8de-490a-82a9-8a3c16e2fdd0-06_645_684_260_639} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} The uniform lamina \(A B C D\) is a square of side \(6 a\). The template \(T\), shown shaded in Figure 1, is formed by removing the right-angled triangle \(E F G\) and the circle, centre \(H\) and radius \(a\), from the square lamina. Triangle \(E F G\) has \(E F = E G = 4 a\), with \(E F\) parallel to \(A B\) and \(E G\) parallel to \(A D\). The distance between \(A B\) and \(E F\) is \(a\) and the distance between \(A D\) and \(E G\) is \(a\). The point \(H\) lies on \(A C\) and the distance of \(H\) from \(B C\) is \(2 a\).
  1. Show that the centre of mass of \(T\) is a distance \(\frac { 4 ( 67 - 3 \pi ) } { 3 ( 28 - \pi ) } a\) from \(A D\). The template \(T\) is suspended from the ceiling by two light inextensible vertical strings. One string is attached to \(T\) at \(A\) and the other string is attached to \(T\) at \(B\) so that \(T\) hangs in equilibrium with \(A B\) horizontal. The weight of \(T\) is \(W\). The tension in the string attached to \(T\) at \(B\) is \(k W\), where \(k\) is a constant.
  2. Find the value of \(k\), giving your answer to 2 decimal places.

3.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{e6e37d85-f8de-490a-82a9-8a3c16e2fdd0-06_645_684_260_639}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

The uniform lamina $A B C D$ is a square of side $6 a$. The template $T$, shown shaded in Figure 1, is formed by removing the right-angled triangle $E F G$ and the circle, centre $H$ and radius $a$, from the square lamina.

Triangle $E F G$ has $E F = E G = 4 a$, with $E F$ parallel to $A B$ and $E G$ parallel to $A D$. The distance between $A B$ and $E F$ is $a$ and the distance between $A D$ and $E G$ is $a$.

The point $H$ lies on $A C$ and the distance of $H$ from $B C$ is $2 a$.
\begin{enumerate}[label=(\alph*)]
\item Show that the centre of mass of $T$ is a distance $\frac { 4 ( 67 - 3 \pi ) } { 3 ( 28 - \pi ) } a$ from $A D$.

The template $T$ is suspended from the ceiling by two light inextensible vertical strings. One string is attached to $T$ at $A$ and the other string is attached to $T$ at $B$ so that $T$ hangs in equilibrium with $A B$ horizontal.

The weight of $T$ is $W$. The tension in the string attached to $T$ at $B$ is $k W$, where $k$ is a constant.
\item Find the value of $k$, giving your answer to 2 decimal places.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2021 Q3 [8]}}