OCR MEI C2 — Question 2 3 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeFind tangent at given point (polynomial/algebraic)
DifficultyEasy -1.2 This is a collection of routine C2 differentiation exercises covering basic power rule application, tangent equations, chord gradients, and first principles derivation. All parts involve standard textbook procedures with no novel problem-solving required—significantly easier than average A-level questions.
Spec1.07g Differentiation from first principles: for small positive integer powers of x1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations

2 Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) when \(y = x ^ { 6 } + \sqrt { x }\).
  1. Find the equation of the tangent to the curve \(y = x ^ { 4 }\) at the point where \(x = 2\). Give your answer in the form \(y = m x + c\).
  2. Calculate the gradient of the chord joining the points on the curve \(y = x ^ { 4 }\) where \(x = 2\) and \(x = 2.1\).
  3. (A) Expand \(( 2 + h ) ^ { 4 }\).
    (B) Simplify \(\frac { ( 2 + h ) ^ { 4 } - 2 ^ { 4 } } { h }\).
    (C) Show how your result in part (iii) (B) can be used to find the gradient of \(y = x ^ { 4 }\) at the point where \(x = 2\).
  4. Calculate the gradient of the chord joining the points on the curve \(y = x ^ { 2 } - 7\) for which \(x = 3\) and \(x = 3.1\).
  5. Given that \(\mathrm { f } ( x ) = x ^ { 2 } - 7\), find and simplify \(\frac { \mathrm { f } ( 3 + h ) - \mathrm { f } ( 3 ) } { h }\).
  6. Use your result in part (ii) to find the gradient of \(y = x ^ { 2 } - 7\) at the point where \(x = 3\), showing your reasoning.
  7. Find the equation of the tangent to the curve \(y = x ^ { 2 } - 7\) at the point where \(x = 3\).
  8. This tangent crosses the \(x\)-axis at the point P . The curve crosses the positive \(x\)-axis at the point Q . Find the distance PQ , giving your answer correct to 3 decimal places.
  9. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{8ff8b67d-1489-4cb1-bcd2-b32db674e29f-3_651_770_242_737} \captionsetup{labelformat=empty} \caption{Fig. 12}
    \end{figure} Fig. 12 shows part of the curve \(y = x ^ { 4 }\) and the line \(y = 8 x\), which intersect at the origin and the point P .
    (A) Find the coordinates of P , and show that the area of triangle OPQ is 16 square units.
    (B) Find the area of the region bounded by the line and the curve.
  10. You are given that \(\mathrm { f } ( x ) = x ^ { 4 }\).
    (A) Complete this identity for \(\mathrm { f } ( x + h )\). $$\mathrm { f } ( x + h ) = ( x + h ) ^ { 4 } = x ^ { 4 } + 4 x ^ { 3 } h + \ldots$$ (B) Simplify \(\frac { \mathrm { f } ( x + h ) - \mathrm { f } ( x ) } { h }\).
    (C) Find \(\lim _ { h \rightarrow 0 } \frac { \mathrm { f } ( x + h ) - \mathrm { f } ( x ) } { h }\).
    (D) State what this limit represents.

Question 2:
\(6x^5 + \frac{1}{x} - 12\) o.e.
AnswerMarks
B1\(6x^5\)
B1\(\frac{1}{x^2}\) soi
B1\(-12\) isw
M1\(3\)
Question 2:

$6x^5 + \frac{1}{x} - 12$ o.e.

B1 | $6x^5$

B1 | $\frac{1}{x^2}$ soi

B1 | $-12$ isw

M1 | $3$
2 Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ when $y = x ^ { 6 } + \sqrt { x }$.
\begin{enumerate}[label=(\roman*)]
\item Find the equation of the tangent to the curve $y = x ^ { 4 }$ at the point where $x = 2$. Give your answer in the form $y = m x + c$.
\item Calculate the gradient of the chord joining the points on the curve $y = x ^ { 4 }$ where $x = 2$ and $x = 2.1$.
\item (A) Expand $( 2 + h ) ^ { 4 }$.\\
(B) Simplify $\frac { ( 2 + h ) ^ { 4 } - 2 ^ { 4 } } { h }$.\\
(C) Show how your result in part (iii) (B) can be used to find the gradient of $y = x ^ { 4 }$ at the point where $x = 2$.
\item Calculate the gradient of the chord joining the points on the curve $y = x ^ { 2 } - 7$ for which $x = 3$ and $x = 3.1$.
\item Given that $\mathrm { f } ( x ) = x ^ { 2 } - 7$, find and simplify $\frac { \mathrm { f } ( 3 + h ) - \mathrm { f } ( 3 ) } { h }$.
\item Use your result in part (ii) to find the gradient of $y = x ^ { 2 } - 7$ at the point where $x = 3$, showing your reasoning.
\item Find the equation of the tangent to the curve $y = x ^ { 2 } - 7$ at the point where $x = 3$.
\item This tangent crosses the $x$-axis at the point P . The curve crosses the positive $x$-axis at the point Q . Find the distance PQ , giving your answer correct to 3 decimal places.
\item \begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{8ff8b67d-1489-4cb1-bcd2-b32db674e29f-3_651_770_242_737}
\captionsetup{labelformat=empty}
\caption{Fig. 12}
\end{center}
\end{figure}

Fig. 12 shows part of the curve $y = x ^ { 4 }$ and the line $y = 8 x$, which intersect at the origin and the point P .\\
(A) Find the coordinates of P , and show that the area of triangle OPQ is 16 square units.\\
(B) Find the area of the region bounded by the line and the curve.
\item You are given that $\mathrm { f } ( x ) = x ^ { 4 }$.\\
(A) Complete this identity for $\mathrm { f } ( x + h )$.

$$\mathrm { f } ( x + h ) = ( x + h ) ^ { 4 } = x ^ { 4 } + 4 x ^ { 3 } h + \ldots$$

(B) Simplify $\frac { \mathrm { f } ( x + h ) - \mathrm { f } ( x ) } { h }$.\\
(C) Find $\lim _ { h \rightarrow 0 } \frac { \mathrm { f } ( x + h ) - \mathrm { f } ( x ) } { h }$.\\
(D) State what this limit represents.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C2  Q2 [3]}}
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