OCR M1 2007 June — Question 1 6 marks

Exam BoardOCR
ModuleM1 (Mechanics 1)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeResultant of three coplanar forces
DifficultyEasy -1.2 This is a straightforward M1 mechanics question requiring only basic vector addition (adding components) and then using Pythagoras and inverse tangent to find magnitude and direction. It's routine bookwork with no problem-solving element, making it easier than average A-level questions overall.
Spec3.03p Resultant forces: using vectors

1 \includegraphics[max width=\textwidth, alt={}, center]{ae5d1e27-5853-48aa-9046-86ce1c1a154a-2_415_823_264_660} Two horizontal forces \(\mathbf { P }\) and \(\mathbf { Q }\) act at the origin O of rectangular coordinates Oxy (see diagram). The components of \(\mathbf { P }\) in the \(x\) - and \(y\)-directions are 14 N and 5 N respectively. The components of \(\mathbf { Q }\) in the \(x\) - and \(y\)-directions are - 9 N and 7 N respectively.
  1. Write down the components, in the \(x\) - and \(y\)-directions, of the resultant of \(\mathbf { P }\) and \(\mathbf { Q }\).
  2. Hence find the magnitude of this resultant, and the angle the resultant makes with the positive \(x\)-axis.

AnswerMarks Guidance
1(i)\(X = 5\), \(Y = 12\) B1
1(i) B1
1(ii)\(R^2 = 5^2 + 12^2\) [2]
1(ii)Magnitude is 13 N M1
1(ii)\(\tan\theta = 12/5\) A1
1(ii)Angle is 67.4° M1
1(ii) [4]
1(i) | $X = 5$, $Y = 12$ | B1 | $X=5$ B0. Both may be seen/implied in (ii)
1(i) | | B1 | No evidence for which value is $X$ or $Y$ available from (ii) award B1 for the pair of values 5 and 12 irrespective of order
1(ii) | $R^2 = 5^2 + 12^2$ | [2] | 
1(ii) | Magnitude is 13 N | M1 | For using $R^2 = X^2 + Y^2$
1(ii) | $\tan\theta = 12/5$ | A1 | Allow 13 from $X=5$
1(ii) | Angle is 67.4° | M1 | For using correct angle in a trig expression
1(ii) | | [4] | SR: $p=14.9$ and $Q=11.4$ giving $R=13±0.1$ B2, Angle = $67.5±/0.5$ B2
1\\
\includegraphics[max width=\textwidth, alt={}, center]{ae5d1e27-5853-48aa-9046-86ce1c1a154a-2_415_823_264_660}

Two horizontal forces $\mathbf { P }$ and $\mathbf { Q }$ act at the origin O of rectangular coordinates Oxy (see diagram). The components of $\mathbf { P }$ in the $x$ - and $y$-directions are 14 N and 5 N respectively. The components of $\mathbf { Q }$ in the $x$ - and $y$-directions are - 9 N and 7 N respectively.\\
(i) Write down the components, in the $x$ - and $y$-directions, of the resultant of $\mathbf { P }$ and $\mathbf { Q }$.\\
(ii) Hence find the magnitude of this resultant, and the angle the resultant makes with the positive $x$-axis.

\hfill \mbox{\textit{OCR M1 2007 Q1 [6]}}