OCR C2 — Question 9 12 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeMixed arithmetic and geometric
DifficultyStandard +0.3 This is a straightforward multi-part question testing basic definitions of arithmetic and geometric progressions. Parts (i) and (ii) require simple formula application (GP: ar^n, AP: a+nd), part (iii) involves solving a quadratic equation, and part (iv) uses the standard sum formula. All techniques are routine for C2 level with no novel problem-solving required, making it slightly easier than average.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum

9. The first two terms of a geometric progression are 2 and \(x\) respectively, where \(x \neq 2\).
  1. Find an expression for the third term in terms of \(x\). The first and third terms of arithmetic progression are 2 and \(x\) respectively.
  2. Find an expression for the 11th term in terms of \(x\). Given that the third term of the geometric progression and the 11th term of the arithmetic progression have the same value,
  3. find the value of \(x\),
  4. find the sum of the first 50 terms of the arithmetic progression.

AnswerMarks Guidance
(i) \(r = \frac{x}{2}\)M1
\(\therefore u_1 = x \times \frac{x}{2} = \frac{1}{2}x^2\)M1 A1
(ii) \(a = 2, a + 2d = x\)M1
\(\therefore d = \frac{1}{2}(x - 2)\)
\(u_{11} = 2 + [10 \times \frac{1}{2}(x - 2)] = 5x - 8\)M1 A1
(iii) \(\frac{1}{2}x^2 = 5x - 8\)M1
\(x^2 - 10x + 16 = 0\)M1
\((x - 2)(x - 8) = 0\)
\(x \neq 2 \therefore x = 8\)A1
(iv) \(d = \frac{1}{2}(8 - 2) = 3\)B1
\(S_{50} = \frac{50}{2}[4 + (49 \times 3)] = 3775\)M1 A1 (12)
AnswerMarks
Total(72)
**(i)** $r = \frac{x}{2}$ | M1 |
$\therefore u_1 = x \times \frac{x}{2} = \frac{1}{2}x^2$ | M1 A1 |

**(ii)** $a = 2, a + 2d = x$ | M1 |
$\therefore d = \frac{1}{2}(x - 2)$ | |
$u_{11} = 2 + [10 \times \frac{1}{2}(x - 2)] = 5x - 8$ | M1 A1 |

**(iii)** $\frac{1}{2}x^2 = 5x - 8$ | M1 |
$x^2 - 10x + 16 = 0$ | M1 |
$(x - 2)(x - 8) = 0$ | |
$x \neq 2 \therefore x = 8$ | A1 |

**(iv)** $d = \frac{1}{2}(8 - 2) = 3$ | B1 |
$S_{50} = \frac{50}{2}[4 + (49 \times 3)] = 3775$ | M1 A1 | (12)

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**Total** | (72) |
9. The first two terms of a geometric progression are 2 and $x$ respectively, where $x \neq 2$.\\
(i) Find an expression for the third term in terms of $x$.

The first and third terms of arithmetic progression are 2 and $x$ respectively.\\
(ii) Find an expression for the 11th term in terms of $x$.

Given that the third term of the geometric progression and the 11th term of the arithmetic progression have the same value,\\
(iii) find the value of $x$,\\
(iv) find the sum of the first 50 terms of the arithmetic progression.

\hfill \mbox{\textit{OCR C2  Q9 [12]}}