CAIE P2 2004 June — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2004
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyModerate -0.3 This is a standard harmonic form question with routine steps: (i) uses the formula R=√(a²+b²) and tan α=b/a, (ii) applies the result to solve a straightforward equation, and (iii) requires recognizing that minimum occurs at R=-5, giving answer 2. All techniques are textbook exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.05g Exact trigonometric values: for standard angles1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

4
  1. Express \(3 \sin \theta + 4 \cos \theta\) in the form \(R \sin ( \theta + \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\), giving the value of \(\alpha\) correct to 2 decimal places.
  2. Hence solve the equation $$3 \sin \theta + 4 \cos \theta = 4.5$$ giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\), correct to 1 decimal place.
  3. Write down the least value of \(3 \sin \theta + 4 \cos \theta + 7\) as \(\theta\) varies.

Question 4:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State answer \(R = 5\)B1
Use trigonometric formulae to find \(\alpha\)M1
Obtain answer \(\alpha = 53.13°\)A1 Total: 3
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Carry out, or indicate need for, calculation of \(\sin^{-1}(4.5/5)\)M1
Obtain answer 11.0°\(\text{A1}\sqrt{}\)
Carry out correct method for the second root e.g. \(180° - 64.16° - 53.13°\)M1
Obtain answer 62.7° and no others in the range\(\text{A1}\sqrt{}\) Total: 4
Ignore answers outside the given range.
Part (iii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State least value is 2\(\text{B1}\sqrt{}\) Total: 1
## Question 4:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State answer $R = 5$ | B1 | |
| Use trigonometric formulae to find $\alpha$ | M1 | |
| Obtain answer $\alpha = 53.13°$ | A1 | **Total: 3** |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Carry out, or indicate need for, calculation of $\sin^{-1}(4.5/5)$ | M1 | |
| Obtain answer 11.0° | $\text{A1}\sqrt{}$ | |
| Carry out correct method for the second root e.g. $180° - 64.16° - 53.13°$ | M1 | |
| Obtain answer 62.7° and no others in the range | $\text{A1}\sqrt{}$ | **Total: 4** |
| | | Ignore answers outside the given range. |

### Part (iii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State least value is 2 | $\text{B1}\sqrt{}$ | **Total: 1** |

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4 (i) Express $3 \sin \theta + 4 \cos \theta$ in the form $R \sin ( \theta + \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$, giving the value of $\alpha$ correct to 2 decimal places.\\
(ii) Hence solve the equation

$$3 \sin \theta + 4 \cos \theta = 4.5$$

giving all solutions in the interval $0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }$, correct to 1 decimal place.\\
(iii) Write down the least value of $3 \sin \theta + 4 \cos \theta + 7$ as $\theta$ varies.

\hfill \mbox{\textit{CAIE P2 2004 Q4 [8]}}