OCR C2 — Question 3 7 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicQuadratic trigonometric equations
TypeShow then solve: sin²/cos² substitution
DifficultyModerate -0.3 This is a standard C2 trigonometric equation requiring the identity cos²x + sin²x = 1 to convert to a quadratic in sin x, then solving using the quadratic formula and finding angles in the given range. It's a textbook exercise with clear steps and no novel insight required, making it slightly easier than average.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

3. (i) Show that the equation $$3 \cos ^ { 2 } x ^ { \circ } + \sin ^ { 2 } x ^ { \circ } + 5 \sin x ^ { \circ } = 0$$ can be written as a quadratic equation in \(\sin \chi ^ { \circ }\).
(ii) Hence solve, for \(0 \leq x < 360\), the equation $$3 \cos ^ { 2 } x ^ { \circ } + \sin ^ { 2 } x ^ { \circ } + 5 \sin x ^ { \circ } = 0$$

3. (i) Show that the equation

$$3 \cos ^ { 2 } x ^ { \circ } + \sin ^ { 2 } x ^ { \circ } + 5 \sin x ^ { \circ } = 0$$

can be written as a quadratic equation in $\sin \chi ^ { \circ }$.\\
(ii) Hence solve, for $0 \leq x < 360$, the equation

$$3 \cos ^ { 2 } x ^ { \circ } + \sin ^ { 2 } x ^ { \circ } + 5 \sin x ^ { \circ } = 0$$

\hfill \mbox{\textit{OCR C2  Q3 [7]}}