CAIE P1 2021 June — Question 3 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2021
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeStandard product of two binomials
DifficultyModerate -0.8 Part (a) is straightforward binomial expansion requiring direct application of the formula for three terms. Part (b) requires multiplying two expansions and collecting terms, which is a standard textbook exercise with clear methodology. The question involves routine algebraic manipulation with no conceptual challenges or novel problem-solving required.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

3
  1. Find the first three terms in the expansion of \(( 3 - 2 x ) ^ { 5 }\) in ascending powers of \(x\).
  2. Hence find the coefficient of \(x ^ { 2 }\) in the expansion of \(( 4 + x ) ^ { 2 } ( 3 - 2 x ) ^ { 5 }\).

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(243\)B1
\(-810x\)B1
\(+1080x^2\)B1
3
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
\((4+x)^2 = 16 + 8x + x^2\)B1
Coefficient of \(x^2\) is \(16 \times 1080 + 8 \times (-810) + 243\)M1 Allow if at least 2 pairs used correctly
\(11043\)A1 Allow \(11043x^2\)
3
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $243$ | B1 | |
| $-810x$ | B1 | |
| $+1080x^2$ | B1 | |
| | **3** | |

## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(4+x)^2 = 16 + 8x + x^2$ | B1 | |
| Coefficient of $x^2$ is $16 \times 1080 + 8 \times (-810) + 243$ | M1 | Allow if at least 2 pairs used correctly |
| $11043$ | A1 | Allow $11043x^2$ |
| | **3** | |
3
\begin{enumerate}[label=(\alph*)]
\item Find the first three terms in the expansion of $( 3 - 2 x ) ^ { 5 }$ in ascending powers of $x$.
\item Hence find the coefficient of $x ^ { 2 }$ in the expansion of $( 4 + x ) ^ { 2 } ( 3 - 2 x ) ^ { 5 }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2021 Q3 [6]}}