CAIE P2 2020 March — Question 7 10 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2020
SessionMarch
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeMultiple angle equations
DifficultyStandard +0.3 This is a straightforward multi-part question requiring standard techniques: solving a quadratic in sin x, differentiating using chain rule, and integrating a trigonometric expression. All steps are routine A-level procedures with no novel insight required, making it slightly easier than average.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08d Evaluate definite integrals: between limits

7 \includegraphics[max width=\textwidth, alt={}, center]{78a9b100-c3bd-4054-b539-ec8304440063-10_551_641_260_751} The diagram shows part of the curve with equation $$y = 4 \sin ^ { 2 } x + 8 \sin x + 3 ,$$ where \(x\) is measured in radians. The curve crosses the \(x\)-axis at the point \(A\) and the shaded region is bounded by the curve and the lines \(x = 0\) and \(y = 0\).
  1. Find the exact \(x\)-coordinate of \(A\).
  2. Find the exact gradient of the curve at \(A\).
  3. Find the exact area of the shaded region.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a):
AnswerMarks Guidance
AnswerMarks Guidance
Solve equation \(y = 0\) to find value of \(x\)M1
Obtain \(\frac{7}{6}\pi\)A1
Question 7(b):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt first derivative using chain ruleM1 OE
Obtain \(\frac{dy}{dx} = 8\sin x\cos x + 8\cos x\)A1 OE
Substitute value from part (a) to find gradient \(-2\sqrt{3}\)A1 Or exact equivalent
Question 7(c):
AnswerMarks Guidance
AnswerMarks Guidance
Express integrand in the form \(k_1 + k_2\cos 2x + k_3\sin x\)\*M1
Obtain correct \(5 - 2\cos 2x + 8\sin x\)A1 OE. Allow unsimplified
Integrate to obtain \(5x - \sin 2x - 8\cos x\)A1
Apply limits 0 and *their* value from part (a) correctlyDM1
Obtain \(\frac{35}{6}\pi + \frac{7}{2}\sqrt{3} + 8\) or exact equivalentA1
## Question 7(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Solve equation $y = 0$ to find value of $x$ | M1 | |
| Obtain $\frac{7}{6}\pi$ | A1 | |

## Question 7(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt first derivative using chain rule | M1 | OE |
| Obtain $\frac{dy}{dx} = 8\sin x\cos x + 8\cos x$ | A1 | OE |
| Substitute value from part (a) to find gradient $-2\sqrt{3}$ | A1 | Or exact equivalent |

## Question 7(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Express integrand in the form $k_1 + k_2\cos 2x + k_3\sin x$ | \*M1 | |
| Obtain correct $5 - 2\cos 2x + 8\sin x$ | A1 | OE. Allow unsimplified |
| Integrate to obtain $5x - \sin 2x - 8\cos x$ | A1 | |
| Apply limits 0 and *their* value from part (a) correctly | DM1 | |
| Obtain $\frac{35}{6}\pi + \frac{7}{2}\sqrt{3} + 8$ or exact equivalent | A1 | |
7\\
\includegraphics[max width=\textwidth, alt={}, center]{78a9b100-c3bd-4054-b539-ec8304440063-10_551_641_260_751}

The diagram shows part of the curve with equation

$$y = 4 \sin ^ { 2 } x + 8 \sin x + 3 ,$$

where $x$ is measured in radians. The curve crosses the $x$-axis at the point $A$ and the shaded region is bounded by the curve and the lines $x = 0$ and $y = 0$.
\begin{enumerate}[label=(\alph*)]
\item Find the exact $x$-coordinate of $A$.
\item Find the exact gradient of the curve at $A$.
\item Find the exact area of the shaded region.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2020 Q7 [10]}}