OCR MEI C1 2008 January — Question 11 12 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2008
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscriminant and conditions for roots
TypeProve/show always positive
DifficultyModerate -0.8 This is a straightforward C1 completing-the-square question with standard parts: completing the square (routine), sketching a parabola, solving a quadratic inequality, and checking if a shifted parabola crosses the x-axis. All parts use basic techniques with no novel problem-solving required, making it easier than average but not trivial due to the multi-part structure.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02e Complete the square: quadratic polynomials and turning points1.02g Inequalities: linear and quadratic in single variable1.02n Sketch curves: simple equations including polynomials

11
  1. Write \(x ^ { 2 } - 5 x + 8\) in the form \(( x - a ) ^ { 2 } + b\) and hence show that \(x ^ { 2 } - 5 x + 8 > 0\) for all values of \(x\).
  2. Sketch the graph of \(y = x ^ { 2 } - 5 x + 8\), showing the coordinates of the turning point.
  3. Find the set of values of \(x\) for which \(x ^ { 2 } - 5 x + 8 > 14\).
  4. If \(\mathrm { f } ( x ) = x ^ { 2 } - 5 x + 8\), does the graph of \(y = \mathrm { f } ( x ) - 10\) cross the \(x\)-axis? Show how you decide.

AnswerMarks Guidance
i \((x - 2.5)^2\) o.e.; \(-2.5^2 + 8\); \((x - 2.5)^2 + 7/4\) o.e.; min \(y = 7/4\) o.e. [so above \(x\) axis] or commenting \((x - 2.5)^2 \geq 0\)Marks: M1, M1, A1, B1 Guidance: ft, dep on \((x - a)^2 + b\) with \(b\) positive; condone starting again, showing \(b^2 - 4ac < 0\) or using calculus
ii correct symmetrical quadratic shape; 8 marked as intercept on \(y\) axis; tp (5/2, 7/4) o.e. or ft from (i)Marks: G1, G1, G1 Guidance: or (0, 8) seen in table
iii \(x^2 - 5x - 6\) seen or used; \(-1\) and \(6\) obtained; \(x < -1\) and \(x > 6\) isw or ft their solnsMarks: M1, M1, M1 Guidance: or \((x - 2.5)^2 [> or =] 12.25\) or \(14 - b\); also implies first M1; if M0, allow B1 for one of \(x < -1\) and \(x > 6\)
iv min \(= (2.5, -8.25)\) or ft from (i) so yes, crossesMarks: M1, A1 Guidance: or M1 for other clear comment re translated 10 down and A1 for referring to min in (i) or graph in (ii); or M1 for correct method for solving \(x^2 - 5x - 2 = 0\) or using \(b^2 - 4ac\) with this and A1 for showing real solns eg \(b^2 - 4ac = 33\); allow M1A0 for valid comment but error in -8.25 ft; allow M1 for showing \(y\) can be neg eg (0, \(-2\)) found and A1 for correct conclusion
Total for Question 11: 12
**i** $(x - 2.5)^2$ o.e.; $-2.5^2 + 8$; $(x - 2.5)^2 + 7/4$ o.e.; min $y = 7/4$ o.e. [so above $x$ axis] or commenting $(x - 2.5)^2 \geq 0$ | **Marks:** M1, M1, A1, B1 | **Guidance:** ft, dep on $(x - a)^2 + b$ with $b$ positive; condone starting again, showing $b^2 - 4ac < 0$ or using calculus | **Total:** 4

**ii** correct symmetrical quadratic shape; 8 marked as intercept on $y$ axis; tp (5/2, 7/4) o.e. or ft from (i) | **Marks:** G1, G1, G1 | **Guidance:** or (0, 8) seen in table | **Total:** 3

**iii** $x^2 - 5x - 6$ seen or used; $-1$ and $6$ obtained; $x < -1$ and $x > 6$ isw or ft their solns | **Marks:** M1, M1, M1 | **Guidance:** or $(x - 2.5)^2 [> or =] 12.25$ or $14 - b$; also implies first M1; if M0, allow B1 for one of $x < -1$ and $x > 6$ | **Total:** 3

**iv** min $= (2.5, -8.25)$ or ft from (i) so yes, crosses | **Marks:** M1, A1 | **Guidance:** or M1 for other clear comment re translated 10 down and A1 for referring to min in (i) or graph in (ii); or M1 for correct method for solving $x^2 - 5x - 2 = 0$ or using $b^2 - 4ac$ with this and A1 for showing real solns eg $b^2 - 4ac = 33$; allow M1A0 for valid comment but error in -8.25 ft; allow M1 for showing $y$ can be neg eg (0, $-2$) found and A1 for correct conclusion | **Total:** 2

**Total for Question 11:** 12
11 (i) Write $x ^ { 2 } - 5 x + 8$ in the form $( x - a ) ^ { 2 } + b$ and hence show that $x ^ { 2 } - 5 x + 8 > 0$ for all values of $x$.\\
(ii) Sketch the graph of $y = x ^ { 2 } - 5 x + 8$, showing the coordinates of the turning point.\\
(iii) Find the set of values of $x$ for which $x ^ { 2 } - 5 x + 8 > 14$.\\
(iv) If $\mathrm { f } ( x ) = x ^ { 2 } - 5 x + 8$, does the graph of $y = \mathrm { f } ( x ) - 10$ cross the $x$-axis? Show how you decide.

\hfill \mbox{\textit{OCR MEI C1 2008 Q11 [12]}}