7
\includegraphics[max width=\textwidth, alt={}, center]{61df367d-741f-4906-8ab9-2f32e8711aa6-10_465_785_260_680}
The diagram shows the curve with parametric equations
$$x = 4 t + \mathrm { e } ^ { 2 t } , \quad y = 6 t \sin 2 t$$
for \(0 \leqslant t \leqslant 1\). The point \(P\) on the curve has parameter \(p\) and \(y\)-coordinate 3 .
- Show that \(p = \frac { 1 } { 2 \sin 2 p }\).
- Show by calculation that the value of \(p\) lies between 0.5 and 0.6 .
- Use an iterative formula, based on the equation in part (a), to find the value of \(p\) correct to 3 significant figures. Use an initial value of 0.55 and give the result of each iteration to 5 significant figures.
- Find the gradient of the curve at \(P\).
If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.