OCR S1 Specimen — Question 2 7 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
SessionSpecimen
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeSketch scatter diagram scenarios
DifficultyStandard +0.3 Part (i) is a routine calculation of Spearman's rank correlation coefficient following a standard algorithm. Part (ii) requires conceptual understanding that Spearman measures monotonic relationships while PMCC measures linear relationships, but sketching a simple curved monotonic relationship (e.g., exponential curve through 5 points) is straightforward once this distinction is understood. This is slightly above average due to the conceptual element in part (ii), but well within reach of a competent S1 student.
Spec5.08e Spearman rank correlation5.08f Hypothesis test: Spearman rank

2 Two independent assessors awarded marks to each of 5 projects. The results were as shown in the table.
Project\(A\)\(B\)\(C\)\(D\)\(E\)
First assessor3891628361
Second assessor5684418562
  1. Calculate Spearman's rank correlation coefficient for the data.
  2. Show, by sketching a suitable scatter diagram, how two assessors might have assessed 5 projects in such a way that Spearman's rank correlation coefficient for their marks was + 1 while the product moment correlation coefficient for their marks was not + 1 . (Your scatter diagram need not be drawn accurately to scale.)

Part (i)
Ranks are: \(\begin{matrix} 1 & 5 & 3 & 4 & 2 \\ 2 & 4 & 1 & 5 & 3 \end{matrix}\)
Values of \(d\) are \(-1, 1, 2, -1, -1\)
AnswerMarks Guidance
\(r_s = 1 - \frac{6 \times 8}{5 \times 24} = 0.6\)B2 For correct ranks (or reversed); B1 if 1 error
M1For correct values of \(d\) or \(d^2\)
M1For use of the Spearman formula
A1For correct answer 0.6 or fractional equivalent
Part (ii)
AnswerMarks Guidance
(e.g. scatter plot showing non-linear increasing relationship)B2 For 5 points, showing any non-linear 'increasing' relationship
**Part (i)**

Ranks are: $\begin{matrix} 1 & 5 & 3 & 4 & 2 \\ 2 & 4 & 1 & 5 & 3 \end{matrix}$

Values of $d$ are $-1, 1, 2, -1, -1$

$r_s = 1 - \frac{6 \times 8}{5 \times 24} = 0.6$ | B2 | For correct ranks (or reversed); B1 if 1 error
| M1 | For correct values of $d$ or $d^2$
| M1 | For use of the Spearman formula
| A1 | For correct answer 0.6 or fractional equivalent

**Part (ii)**

(e.g. scatter plot showing non-linear increasing relationship) | B2 | For 5 points, showing any non-linear 'increasing' relationship

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2 Two independent assessors awarded marks to each of 5 projects. The results were as shown in the table.

\begin{center}
\begin{tabular}{ | l | c c c c c | }
\hline
Project & $A$ & $B$ & $C$ & $D$ & $E$ \\
\hline
First assessor & 38 & 91 & 62 & 83 & 61 \\
Second assessor & 56 & 84 & 41 & 85 & 62 \\
\hline
\end{tabular}
\end{center}

(i) Calculate Spearman's rank correlation coefficient for the data.\\
(ii) Show, by sketching a suitable scatter diagram, how two assessors might have assessed 5 projects in such a way that Spearman's rank correlation coefficient for their marks was + 1 while the product moment correlation coefficient for their marks was not + 1 . (Your scatter diagram need not be drawn accurately to scale.)

\hfill \mbox{\textit{OCR S1  Q2 [7]}}