2 The solutions of the equation \(5 | x | = 5 - 2 x\) are \(x = a\) and \(x = b\), where \(a < b\).
Find the value of \(| 3 a - 1 | + | 7 b - 1 |\).
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Question 2:
Answer Marks
Guidance
Answer Mark
Guidance
Solve \(5x = 5 - 2x\) to obtain \(x = \frac{5}{7}\) B1
Allow AWRT 0.714
Attempt solution of linear equation where signs of \(5x\) and \(2x\) are the same M1
Obtain \(x = -\frac{5}{3}\) A1
Allow AWRT −1.67
Substitute *their* values correctly M1
Substitution must be seen unless implied by a correct answer. *Their* values must come from consideration of \(5
Obtain \( -6
+
Alternative: State or imply non-modulus equation \(25x^2 = (5-2x)^2\)B1
Attempt solution of 3-term quadratic equation M1
Obtain \(-\frac{5}{3}\) and \(\frac{5}{7}\) A1
Allow AWRT 0.714 and AWRT −1.67
Substitute *their* values correctly M1
Substitution must be seen unless implied by a correct answer. *Their* values must come from consideration of \(5
Obtain \( -6
+
Total 5
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## Question 2:
| Answer | Mark | Guidance |
|--------|------|----------|
| Solve $5x = 5 - 2x$ to obtain $x = \frac{5}{7}$ | B1 | Allow AWRT 0.714 |
| Attempt solution of linear equation where signs of $5x$ and $2x$ are the same | M1 | |
| Obtain $x = -\frac{5}{3}$ | A1 | Allow AWRT −1.67 |
| Substitute *their* values correctly | M1 | Substitution must be seen unless implied by a correct answer. *Their* values must come from consideration of $5|x| = 5 - 2x$ |
| Obtain $|-6| + |4|$ and hence 10 | A1 | |
| **Alternative:** State or imply non-modulus equation $25x^2 = (5-2x)^2$ | B1 | |
| Attempt solution of 3-term quadratic equation | M1 | |
| Obtain $-\frac{5}{3}$ and $\frac{5}{7}$ | A1 | Allow AWRT 0.714 and AWRT −1.67 |
| Substitute *their* values correctly | M1 | Substitution must be seen unless implied by a correct answer. *Their* values must come from consideration of $5|x| = 5 - 2x$ |
| Obtain $|-6| + |4|$ and hence 10 | A1 | |
| **Total** | **5** | |
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2 The solutions of the equation $5 | x | = 5 - 2 x$ are $x = a$ and $x = b$, where $a < b$.\\
Find the value of $| 3 a - 1 | + | 7 b - 1 |$.\\
\hfill \mbox{\textit{CAIE P2 2021 Q2 [5]}}