CAIE P2 2021 June — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2021
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeFind gradient at given parameter
DifficultyStandard +0.3 This is a straightforward parametric differentiation question requiring standard techniques: solving a logarithm equation using log laws in part (a), then applying the chain rule dy/dx = (dy/dt)/(dx/dt) with product rule for dy/dt in part (b). All steps are routine for P2 level with no novel problem-solving required, making it slightly easier than average.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

4 A curve has parametric equations $$x = \ln ( 2 t + 6 ) - \ln t , \quad y = t \ln t$$
  1. Find the value of \(t\) at the point \(P\) on the curve for which \(x = \ln 4\).
  2. Find the exact gradient of the curve at \(P\).

Question 4(a):
AnswerMarks Guidance
AnswerMark Guidance
Equate \(x\) to \(\ln4\) and use relevant logarithm propertyM1
Obtain equation with no logarithm present, \(\dfrac{2t+6}{t} = 4\)A1 OE
Obtain \(t = 3\)A1
Question 4(b):
AnswerMarks Guidance
AnswerMark Guidance
Obtain \(\dfrac{dx}{dt} = \dfrac{2}{2t+6} - \dfrac{1}{t}\)B1
Use product rule to find \(\dfrac{dy}{dt}\)M1
Obtain \(\ln t + t \times \dfrac{1}{t}\)A1
Divide to obtain \(\dfrac{dy}{dx}\) using *their* \(\dfrac{dy}{dt}\) and \(\dfrac{dx}{dt}\) correctlyDM1 Must have at least B1 or M1; Do not condone incorrect inverting of terms unless a correct statement is seen initially
Obtain \(-6(\ln3 + 1)\)A1 or exact equivalents
## Question 4(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Equate $x$ to $\ln4$ and use relevant logarithm property | M1 | |
| Obtain equation with no logarithm present, $\dfrac{2t+6}{t} = 4$ | A1 | OE |
| Obtain $t = 3$ | A1 | |

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## Question 4(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain $\dfrac{dx}{dt} = \dfrac{2}{2t+6} - \dfrac{1}{t}$ | B1 | |
| Use product rule to find $\dfrac{dy}{dt}$ | M1 | |
| Obtain $\ln t + t \times \dfrac{1}{t}$ | A1 | |
| Divide to obtain $\dfrac{dy}{dx}$ using *their* $\dfrac{dy}{dt}$ and $\dfrac{dx}{dt}$ correctly | DM1 | Must have at least B1 or M1; Do not condone incorrect inverting of terms unless a correct statement is seen initially |
| Obtain $-6(\ln3 + 1)$ | A1 | or exact equivalents |

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4 A curve has parametric equations

$$x = \ln ( 2 t + 6 ) - \ln t , \quad y = t \ln t$$
\begin{enumerate}[label=(\alph*)]
\item Find the value of $t$ at the point $P$ on the curve for which $x = \ln 4$.
\item Find the exact gradient of the curve at $P$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2021 Q4 [8]}}