OCR S1 2006 June — Question 5 9 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2006
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeTwo unknowns from sum and expectation
DifficultyModerate -0.8 This is a straightforward S1 question requiring two standard techniques: using the sum of probabilities equals 1 and the definition of expectation to form simultaneous equations. The algebra is simple (linear equations), and part (ii) is routine calculation of variance/standard deviation using the standard formula. No problem-solving insight needed, just direct application of formulas.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

5 The probability distribution of a discrete random variable, \(X\), is given in the table.
\(x\)0123
\(\mathrm { P } ( X = x )\)\(\frac { 1 } { 3 }\)\(\frac { 1 } { 4 }\)\(p\)\(q\)
It is given that the expectation, \(\mathrm { E } ( X )\), is \(1 \frac { 1 } { 4 }\).
  1. Calculate the values of \(p\) and \(q\).
  2. Calculate the standard deviation of \(X\).

AnswerMarks Guidance
5(i)\(^1/_{3} + ^1/_{4} + p + q = 1\) oe \(0 \times ^1/_{3} + 1 \times ^1/_{4} + 2p + 3q = 1\frac{1}{4}\) oe equalize coeffs, eg mult eqn (i) by 2 or 3 Or make \(p\) or \(q\) subject of (i) or (ii) B1: —; B1: —
\(p = ^1/_{12}, q = ^1/_{6}\) oeM1: —; A1A1: 5 allow one error. If their equns subst or subtr not nec'y
5(ii)\(\Sigma x^2p\) (not \(i4\) or \(i3\) etc) \(= (2^1/_{4})\) \((1/_{10})^2\) M1: —; M1: —
\(\text{ft (i) (0S } p, q < 1) \text{ or letters } p, q \text{ both M1s cao}\)
\(= 1.1875\) or \(1^7/_{16}\) oe sd \(=\sqrt{(\text{their } 1.1875)} = 1.09\) (3 sfs)A1: —; B1f: 4 dep 1st M1 &/(+ve no.) eg \(\sqrt{2.75 = 1.66}\)
Total: 9
5(i) | $^1/_{3} + ^1/_{4} + p + q = 1$ oe $0 \times ^1/_{3} + 1 \times ^1/_{4} + 2p + 3q = 1\frac{1}{4}$ oe equalize coeffs, eg mult eqn (i) by 2 or 3 Or make $p$ or $q$ subject of (i) or (ii) | B1: —; B1: — | |
| $p = ^1/_{12}, q = ^1/_{6}$ oe | M1: —; A1A1: 5 | allow one error. If their equns subst or subtr not nec'y |

5(ii) | $\Sigma x^2p$ (not $i4$ or $i3$ etc) $= (2^1/_{4})$ $(1/_{10})^2$ | M1: —; M1: — | $\geq 2 \text{ non-zero terms correct, dep +ve result indep if +ve result or } , x-(1^r_{1/})/^p$ (≥ 2 (non-(0) terms correct): M2 |
| | | $\text{ft (i) (0S } p, q < 1) \text{ or letters } p, q \text{ both M1s cao}$ | |
| $= 1.1875$ or $1^7/_{16}$ oe sd $=\sqrt{(\text{their } 1.1875)} = 1.09$ (3 sfs) | A1: —; B1f: 4 | dep 1st M1 &/(+ve no.) eg $\sqrt{2.75 = 1.66}$ |

**Total: 9**

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5 The probability distribution of a discrete random variable, $X$, is given in the table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\hline
$x$ & 0 & 1 & 2 & 3 \\
\hline
$\mathrm { P } ( X = x )$ & $\frac { 1 } { 3 }$ & $\frac { 1 } { 4 }$ & $p$ & $q$ \\
\hline
\end{tabular}
\end{center}

It is given that the expectation, $\mathrm { E } ( X )$, is $1 \frac { 1 } { 4 }$.\\
(i) Calculate the values of $p$ and $q$.\\
(ii) Calculate the standard deviation of $X$.

\hfill \mbox{\textit{OCR S1 2006 Q5 [9]}}