CAIE P2 2020 June — Question 7 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2020
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind constant from definite integral
DifficultyStandard +0.3 This is a straightforward multi-part question requiring standard integration techniques (logarithm and polynomial), algebraic rearrangement, and simple iteration. Part (a) involves routine integration and algebra, part (b) is basic substitution to verify bounds, and part (c) is mechanical iteration with no conceptual challenge. Slightly above average due to the multi-step nature and iteration component, but all techniques are standard A-level fare.
Spec1.08d Evaluate definite integrals: between limits1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

7 It is given that \(\int _ { 0 } ^ { a } \left( \frac { 4 } { 2 x + 1 } + 8 x \right) \mathrm { d } x = 10\), where \(a\) is a positive constant.
  1. Show that \(a = \sqrt { 2.5 - 0.5 \ln ( 2 a + 1 ) }\).
  2. Using the equation in part (a), show by calculation that \(1 < a < 2\).
  3. Use an iterative formula, based on the equation in part (a), to find the value of \(a\) correct to 4 significant figures. Give the result of each iteration to 6 significant figures.

Question 7(a):
AnswerMarks Guidance
AnswerMark Guidance
Integrate to obtain the form \(k_1\ln(2x+1) + k_2x^2\)*M1
Obtain correct \(2\ln(2x+1) + 4x^2\)A1
Use limits correctly and attempt rearrangementDM1
Confirm \(a = \sqrt{2.5 - 0.5\ln(2a+1)}\)A1 AG
Question 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Consider sign of \(a - \sqrt{2.5 - 0.5\ln(2a+1)}\) or equivalent for 1 and 2M1
Obtain \(-0.3...\) and \(0.6...\) or equivalents and justify conclusionA1
Question 7(c):
AnswerMarks Guidance
AnswerMark Guidance
Use iteration process correctly at least onceM1
Obtain final answer \(1.358\)A1
Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval \([1.3575, 1.3585]\)A1
## Question 7(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Integrate to obtain the form $k_1\ln(2x+1) + k_2x^2$ | *M1 | |
| Obtain correct $2\ln(2x+1) + 4x^2$ | A1 | |
| Use limits correctly and attempt rearrangement | DM1 | |
| Confirm $a = \sqrt{2.5 - 0.5\ln(2a+1)}$ | A1 | AG |

## Question 7(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Consider sign of $a - \sqrt{2.5 - 0.5\ln(2a+1)}$ or equivalent for 1 and 2 | M1 | |
| Obtain $-0.3...$ and $0.6...$ or equivalents and justify conclusion | A1 | |

## Question 7(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use iteration process correctly at least once | M1 | |
| Obtain final answer $1.358$ | A1 | |
| Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval $[1.3575, 1.3585]$ | A1 | |

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7 It is given that $\int _ { 0 } ^ { a } \left( \frac { 4 } { 2 x + 1 } + 8 x \right) \mathrm { d } x = 10$, where $a$ is a positive constant.
\begin{enumerate}[label=(\alph*)]
\item Show that $a = \sqrt { 2.5 - 0.5 \ln ( 2 a + 1 ) }$.
\item Using the equation in part (a), show by calculation that $1 < a < 2$.
\item Use an iterative formula, based on the equation in part (a), to find the value of $a$ correct to 4 significant figures. Give the result of each iteration to 6 significant figures.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2020 Q7 [9]}}