8. [In this question, \(\mathbf { i }\) and \(\mathbf { j }\) are horizontal unit vectors directed due east and due north respectively and position vectors are given relative to a fixed origin \(O\).] Two ships, \(A\) and \(B\), are moving with constant velocities.
The velocity of \(A\) is \(( 3 \mathbf { i } + 12 \mathbf { j } ) \mathrm { kmh } ^ { - 1 }\) and the velocity of \(B\) is \(( p \mathbf { i } + q \mathbf { j } ) \mathrm { kmh } ^ { - 1 }\)

1. Find the speed of \(A\). The ships are modelled as particles.
   At 12 noon, \(A\) is at the point with position vector \(( - 9 \mathbf { i } + 6 \mathbf { j } ) \mathrm { km }\) and \(B\) is at the point with position vector \(( 16 \mathbf { i } + 6 \mathbf { j } ) \mathrm { km }\). At time \(t\) hours after 12 noon, $$\overrightarrow { A B } = [ ( 25 - 12 t ) \mathbf { i } - 9 t \mathbf { j } ] \mathrm { km }$$
2. Find the value of \(p\) and the value of \(q\).
3. Find the bearing of \(A\) from \(B\) when the ships are 15 km apart, giving your answer to the nearest degree.
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