| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2019 |
| Session | January |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Moments |
| Type | Beam on point of tilting |
| Difficulty | Standard +0.3 This is a standard M1 moments question involving taking moments about a pivot point to find limiting positions. Part (a) requires a single moment equation about R, part (b) is a modelling statement, and part (c) extends to finding a minimum mass. All techniques are routine for M1 students with no novel insight required, making it slightly easier than average. |
| Spec | 3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(M(R),\ 40g(x-3) + 2.5g \times 2 = 30g \times 0.5\) | M1 A2 | Moments about \(R\); equation in \(x\) only. M0 if reaction at \(P\) is non-zero. \(-1\) each error |
| \(x = 3.25\) m from \(P\) | A1 | \(\frac{13}{4}\) m oe. Allow 3.3 m |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Mass of box concentrated at point \(Q\) | B1 | B1 for *mass* or *weight* of box acts at \(Q\). B0 if extra wrong answers |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(M(R),\ 3Mg + 30g \times 0.5 = 2.5g \times 2 + 40g \times 2\) | M1 A2 | Moments about \(R\); equation in \(M\) only. M0 if reaction at \(P\) non-zero. \(-1\) each error |
| \(M = \frac{70}{3}\), 23 or better | A1 | Accept 24 |
# Question 4:
## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $M(R),\ 40g(x-3) + 2.5g \times 2 = 30g \times 0.5$ | M1 A2 | Moments about $R$; equation in $x$ only. M0 if reaction at $P$ is non-zero. $-1$ each error |
| $x = 3.25$ m from $P$ | A1 | $\frac{13}{4}$ m oe. Allow 3.3 m |
## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Mass of box concentrated at point $Q$ | B1 | B1 for *mass* or *weight* of box acts at $Q$. B0 if extra wrong answers |
## Part (c)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $M(R),\ 3Mg + 30g \times 0.5 = 2.5g \times 2 + 40g \times 2$ | M1 A2 | Moments about $R$; equation in $M$ only. M0 if reaction at $P$ non-zero. $-1$ each error |
| $M = \frac{70}{3}$, 23 or better | A1 | Accept 24 |
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4.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{0d5a56ba-6a33-4dc8-b612-d2957211124f-10_410_1143_258_404}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}
A boy sees a box on the end $Q$ of a plank $P Q$ which overhangs a swimming pool. The plank has mass 30 kg , is 5 m long and rests in a horizontal position on two bricks. The bricks are modelled as smooth supports, one acting on the rod at $P$ and one acting on the rod at $R$, where $P R = 3 \mathrm {~m}$. The support at $R$ is on the edge of the swimming pool, as shown in Figure 2. The boy has mass 40 kg and the box has mass 2.5 kg . The plank is modelled as a uniform rod and the boy and the box are modelled as particles.
The boy steps on to the plank at $P$ and begins to walk slowly along the plank towards the box.
\begin{enumerate}[label=(\alph*)]
\item Find the distance he can walk along the plank from $P$ before the plank starts to tilt.
\item State how you have used, in your working, the fact that the box is modelled as a particle.
A rock of mass $M \mathrm {~kg}$ is placed on the plank at $P$. The boy is then able to walk slowly along the plank to the box at the end $Q$ without the plank tilting. The rock is modelled as a particle.
\item Find the smallest possible value of $M$.
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2019 Q4 [9]}}