| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2019 |
| Session | January |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Impulse and momentum (advanced) |
| Type | Angle change from impulse |
| Difficulty | Moderate -0.3 This is a straightforward M2 impulse-momentum question requiring standard vector manipulation: apply impulse-momentum theorem to find final velocity, then use dot product or tan to find angle change. The calculations are routine with no conceptual difficulty beyond knowing the basic formula, making it slightly easier than average. |
| Spec | 6.03c Momentum in 2D: vector form6.03f Impulse-momentum: relation |
\begin{enumerate}
\item A particle of mass 0.75 kg is moving with velocity ( $4 \mathbf { i } + \mathbf { j }$ ) $\mathrm { m } \mathrm { s } ^ { - 1 }$ when it receives an impulse ( $- 6 \mathbf { i } + 4 \mathbf { j }$ ) N s. impulse $( - 6 \mathbf { i } + 4 \mathbf { j } )$ N s.
\end{enumerate}
\section*{Find \\
Find}
$$\begin{aligned}
& \text { (a) the velocity of the particle immediately after receiving the impulse, } \\
& \text { (b) the size of the angle through which the path of the particle is deflected as a result of } \\
& \text { the impulse. }
\end{aligned}$$
(3)\\
\hfill \mbox{\textit{Edexcel M2 2019 Q2 [6]}}