Edexcel M2 2018 January — Question 4 13 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2018
SessionJanuary
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeCollision followed by wall impact
DifficultyStandard +0.3 This is a standard M2 collision problem with two stages: particle-particle collision using conservation of momentum and Newton's restitution law, followed by a wall collision. Part (a) requires routine application of collision formulas, part (b) is a straightforward inequality proof, and part (c) involves finding conditions for a second collision. While multi-step, all techniques are standard M2 material with no novel insight required, making it slightly easier than average.
Spec6.03b Conservation of momentum: 1D two particles6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact

  1. A particle \(P\) of mass \(2 m\) is moving in a straight line with speed \(u\) on a smooth horizontal plane. The particle \(P\) collides directly with a particle \(Q\), of mass \(m\), which is moving on the plane along the same straight line as \(P\) but in the opposite direction to \(P\). Immediately before the collision the speed of \(Q\) is \(3 u\). The coefficient of restitution between \(P\) and \(Q\) is \(e\), where \(e > \frac { 1 } { 8 }\)
    1. Find, in terms of \(u\) and \(e\),
      1. the speed of \(P\) immediately after the collision,
      2. the speed of \(Q\) immediately after the collision.
    2. Show that, for all possible values of \(e\), the direction of motion of \(P\) is reversed by the collision.
    After the collision, \(Q\) strikes a smooth fixed vertical wall, which is perpendicular to the direction of motion of \(Q\), and rebounds. The coefficient of restitution between \(Q\) and the wall is \(f\). Given that \(e = \frac { 3 } { 4 }\) and that there is a second collision between \(Q\) and \(P\),
  2. find the range of possible values of \(f\).

Question 4(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Conservation of momentumM1 Dimensionally correct. All terms required. Condone sign errors
\(2mu - 3mu = -2mv_P + mv_Q\ (-u = -2v_P + v_Q)\)A1 Correct unsimplified equation
Impact lawM1 Must be used the right way round. Condone sign errors.
\(4eu = v_P + v_Q\)A1 Correct unsimplified equation. Signs consistent with CLM equation
Solve simultaneous equations for \(v_P\) or \(v_Q\)DM1 Dependent on the 2 preceding M marks
\(v_P = \frac{u(1+4e)}{3}\)A1 One correct (must be positive) or equivalent
\(v_Q = \frac{u(8e-1)}{3}\)A1 Both correct (must be positive) or equivalent
Question 4(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\frac{u(1+4e)}{3} > 0\)M1 Working from a correct inequality for their \(v_P\)
Always true because \(e \geq 0\) \(\left(\text{or } e > \frac{1}{8}\right)\)A1 Correct justification from correct work
Question 4(c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(e = \frac{3}{4} \Rightarrow v_Q = \frac{5u}{3}\)B1 Seen or implied
Speed of \(Q\) after collision \(= fv_Q\)M1 Impact law for collision with the wall
To collide with \(P\): \(fv_2 > v_1 = \frac{4u}{3}\)M1 Correct inequality for second collision
\(1 \geq f > \frac{4}{5}\)A1 Both limits required
## Question 4(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Conservation of momentum | M1 | Dimensionally correct. All terms required. Condone sign errors |
| $2mu - 3mu = -2mv_P + mv_Q\ (-u = -2v_P + v_Q)$ | A1 | Correct unsimplified equation |
| Impact law | M1 | Must be used the right way round. Condone sign errors. |
| $4eu = v_P + v_Q$ | A1 | Correct unsimplified equation. Signs consistent with CLM equation |
| Solve simultaneous equations for $v_P$ or $v_Q$ | DM1 | Dependent on the 2 preceding M marks |
| $v_P = \frac{u(1+4e)}{3}$ | A1 | One correct (must be positive) or equivalent |
| $v_Q = \frac{u(8e-1)}{3}$ | A1 | Both correct (must be positive) or equivalent |

---

## Question 4(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{u(1+4e)}{3} > 0$ | M1 | Working from a correct inequality for their $v_P$ |
| Always true because $e \geq 0$ $\left(\text{or } e > \frac{1}{8}\right)$ | A1 | Correct justification from correct work |

---

## Question 4(c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $e = \frac{3}{4} \Rightarrow v_Q = \frac{5u}{3}$ | B1 | Seen or implied |
| Speed of $Q$ after collision $= fv_Q$ | M1 | Impact law for collision with the wall |
| To collide with $P$: $fv_2 > v_1 = \frac{4u}{3}$ | M1 | Correct inequality for second collision |
| $1 \geq f > \frac{4}{5}$ | A1 | Both limits required |

---
\begin{enumerate}
  \item A particle $P$ of mass $2 m$ is moving in a straight line with speed $u$ on a smooth horizontal plane. The particle $P$ collides directly with a particle $Q$, of mass $m$, which is moving on the plane along the same straight line as $P$ but in the opposite direction to $P$. Immediately before the collision the speed of $Q$ is $3 u$. The coefficient of restitution between $P$ and $Q$ is $e$, where $e > \frac { 1 } { 8 }$\\
(a) Find, in terms of $u$ and $e$,\\
(i) the speed of $P$ immediately after the collision,\\
(ii) the speed of $Q$ immediately after the collision.\\
(b) Show that, for all possible values of $e$, the direction of motion of $P$ is reversed by the collision.
\end{enumerate}

After the collision, $Q$ strikes a smooth fixed vertical wall, which is perpendicular to the direction of motion of $Q$, and rebounds. The coefficient of restitution between $Q$ and the wall is $f$.

Given that $e = \frac { 3 } { 4 }$ and that there is a second collision between $Q$ and $P$,\\
(c) find the range of possible values of $f$.

\hfill \mbox{\textit{Edexcel M2 2018 Q4 [13]}}